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vovangra [49]
3 years ago
14

How many combinations of 6 students can a teacher choose from 30 students

Mathematics
2 answers:
taurus [48]3 years ago
6 0
Since unique combinations of students is independent of order, ie order does not matter...

n!/(k!(n-k)!), n=number of choices possible, k=number of choices made...

30!/(6!*24!)

593775


romanna [79]3 years ago
4 0
I believe you just multiply the number of students by the number of students in each combination

30*6= 180 combinations
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Answer:

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Given:

∆ABC

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Angle B = 180 - (105+28)

Angle B = 180 - 133

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b/0.7314 = 18/0.4695

Cross multiply

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