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vovangra [49]
3 years ago
14

How many combinations of 6 students can a teacher choose from 30 students

Mathematics
2 answers:
taurus [48]3 years ago
6 0
Since unique combinations of students is independent of order, ie order does not matter...

n!/(k!(n-k)!), n=number of choices possible, k=number of choices made...

30!/(6!*24!)

593775


romanna [79]3 years ago
4 0
I believe you just multiply the number of students by the number of students in each combination

30*6= 180 combinations
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Answer:

1. $82,500

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Step-by-step explanation:

The computation is shown below:

Given that

1. Ratio between two computers is 3:2

And the first computer cost is $55,000

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