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vovangra [49]
3 years ago
14

How many combinations of 6 students can a teacher choose from 30 students

Mathematics
2 answers:
taurus [48]3 years ago
6 0
Since unique combinations of students is independent of order, ie order does not matter...

n!/(k!(n-k)!), n=number of choices possible, k=number of choices made...

30!/(6!*24!)

593775


romanna [79]3 years ago
4 0
I believe you just multiply the number of students by the number of students in each combination

30*6= 180 combinations
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The polynomial of degree 4, P ( x ) , has a root of multiplicity 2 at x = 1 and roots of multiplicity 1 at x = 0 and x = − 2 . I
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We want to find a polynomial given that we know its roots and a point on the graph.

We will find the polynomial:

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Here we know that the roots are:

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We can write the polynomial as:

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If you want to learn more, you can read:

brainly.com/question/11536910

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