Answer:
A(2,2)
Step-by-step explanation:
Let the vertex A has coordinates 
Vectors AB and AB' are perpendicular, then

Vectors AC and AC' are perpendicular, then

Now, solve the system of two equations:

Subtract these two equations:

Substitute it into the first equation:

Then

Rotation by 90° counterclockwise about A(2,2) gives image points B' and C' (see attached diagram)
Looking at this in terms of sets, let's call O the set of all owls, and F the set of all things that can fly. What this original statement is saying every animal that's a member of the set of all owls is also a member of the set of all things that can fly, or in other words, O⊂F (O is a subset of F). Negating this tells us that, while there's <em>at least one</em> element of O that also belongs to F, O is not contained entirely in F (O⊆F, in notation), so a good negation or our original statement might be:
<em>Not all owls can fly.</em>
Answer: b=0
Step-by-step explanation:
0.5b+4=2(b+2)
0.5b+4=2b+4
4=1.5b+4
0=1.5b
b=0
I guess that u = μ & that a=σ. If so:
μ =100 & that σ =20 & x=20
Z score = (x-μ) / σ ==> Z score = (90-100)/20 ==> Z = - 0.5
Answer:

Step-by-step explanation:
Simplify the radical by breaking the radicand up into a product of known factors.
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