A line with a slope of -3 that passes through the point (2,4)

What are the domain and range of the function f(x) = 3x 5?.

Bingel [31]

The domain and range of the given function both are the real numbers.

<h2>Given that:</h2>

The domain and range of function f(x) = 3x + 5 has to be found.

<h2>Explanation for domain and range:</h2>

Considering working in real numbers, domain is $\mathbb{R}$ and range is $\mathbb{R}$ too.

Domain can be complex numbers too, but for the sake of daily life cases, we consider working in real numbers.

Thinking of it as equation of straight line can help.

The given function is monotonically increasing and continuous.

Thus Range can be calculated as interval ( f(min value of domain), f(max value of domain) ) which gives us $\mathbb{R}$ as range.

Below is the plot of f(x) = 3x + 5 in real number plane.

In fact, any linear equation of the form

$y = mx + c ; \: \: c \in R \: and \: m \in {R-\{0\}}$

has both domain and range as real numbers.

For more information, refer to:

brainly.com/question/12208715

7 0

3 years ago

Read 2 more answers

Find the exact amount of water that dripped each hour

inn [45]

Answer:

Not physically possible

Step-by-step explanation:

5 0

3 years ago

What is the closed linear form of the sequence of the negative even integers starting with -2?

Snowcat [4.5K]

Hello,

n=1,2,3,.... and not 0

Answer B a(n)=-2*n

4 0

4 years ago

Read 2 more answers

What is 17/15 as a mixed number and 2 31/18

inna [77]

17/15 as a mixed number is 1 2/15. 2 31/18 as a mixed number is 54 13/18.

6 0

3 years ago

The price of products may increase due to inflation and decrease due to depreciation. Marco is studying the change in the price

inn [45]

Answer:

Product A has a greater percentage change in price.

Step-by-step explanation:

Part A:

The price f product A, f (<em>x</em>) after <em>x</em> years is given by:

$f(x) = 0.69\cdot(1.03)^{x}$

After <em>x</em> = 0 years, the price of product A is:

$f(0) = 0.69\cdot(1.03)^{0}=0.69$

After <em>x</em> = 1 years, the price of product A is:

$f(1) = 0.69\cdot(1.03)^{1}=0.69\cdot (1+0.03)=0.69\cdot (1+3\%)$

After 1 year, the price of product A is 3% times more than the original price.

This means that after one year, the new price is 103% of the original price, which means the price product A is increasing by 3%.

Again after <em>x</em> = 2 years, the price of product A is:

$f(2) = 0.69\cdot(1.03)^{2}=[0.69\cdot (1+3\%)]\times (1.03)$

This implies that after 2 years, the price of product A is 103% of the price after year 1.

This implies that the price of product A is 3% more than the previous year.

Thus, the price of product A is increasing each year by 3%.

Part B:

The data for Product B is as follows:

Time (t) Price [f (t)]

1 10,100

2 10,201

3 10,303.01

4 10,406.04

Product B is clearly increasing in price.

Consider the changes in price of Product B in the following intervals of years:

Year 1 - Year 2:

Price in year 1 = $10,100

Price in Year 2 = $10,201

Compute the increase percentage as follows:

$\text{Increase}\%=\frac{10201-10100}{10100}=0.01=1\%$

Year 2 - Year 3:

Price in Year 2 = $10,201

Price in year 3 = $10,303.01

Compute the increase percentage as follows:

$\text{Increase}\%=\frac{10303.01-10201}{10201}=0.01=1\%$

Year 3 - Year 4

Price in year 3 = $10,303.01

Price in Year 4 = $10,406.04

Compute the increase percentage as follows:

$\text{Increase}\%=\frac{10,406.04-10303.01}{10303.01}=0.09999\approx 0.01=1\%$

It is quite clear that the price of product B increases by 1% each year.

Thus, Product A has a greater percentage change in price.

3 0

3 years ago