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Len [333]
3 years ago
7

A line with a slope of -3 that passes through the point (2,4)

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
4 0
4 = 2(-3) + b
4 = -6 + b
10 = b

y = -3x + 10
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Solve the equation for y<br> 1/3x+y=4
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Write an algebraic expression for product of 10 and the sum of x and 8
egoroff_w [7]
That would be the same as : 10 × (x + 8)

Okay, so it's asking for the product of 10, and the sum of 8 and k. Sum is the answer to an addition problem, so that would make the last of it 8 + k. And we'd be multiplying this with 10, so that would make it : 10 × (x + 8)
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I need help with this question please.
vredina [299]

Answer:

tan(2x)=-24/7

Step-by-step explanation:

Since tan(x)=sin(x)/cos(x)

We are going to need sin(x) any time, so lets find it right away.

To do this, remember that. sin(x)^2 + cos(x)^2=1

so. sin(x)= \sqrt{1 - (cos(x)^{2} )}=\sqrt{1-(-4/5)^{2} }

This leads to.

\sqrt{\frac{25-16}{25} } =\sqrt{\frac{9}{25} }=+/- 3-5

We have obtained two solutions, -3/5 and 3/5.

We need to pick one, since not all of them are correct for our scenario, in this case, we've been told that x belongs to the range [180, 270], in this range, sin(x)<0.

So in our previous solution, we have that sin(x)= -3/5

Now, to find tang(2x), we need to apply the definition

Tang(2x)=sin(2x)/cos(2x).

Lets remember that

sin(2x)=2*sin(x)*cos(x)

cos(2x)=cos(x)^2 - sin(x)^2.

Lets evaluate our given result.

sin(2x)=2*(-3/5)*(4/5)=-24/25

cos(2x)=(-4/5)^2 - (3/5)^2=7/25

Hence

tan(2x)= -(24/25) / (7/25)=-24/7

5 0
3 years ago
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