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Anna007 [38]
3 years ago
9

A tennis player moves in a straight-line path as shown in the figure below. find her average velocity in the following time inte

rvals.
Mathematics
1 answer:
Andreyy893 years ago
4 0
To find the average velocity in a velocity-time graph at a particular interval, simply determine the gradient at that particular interval. 

<span>a. average velocity= 4/1 </span>
<span>= 4m/s </span>

<span>b. average velocity from 1 to 2.5s= 6/(2.5-1) </span>
<span>= 4m/s </span>

<span>average velocity from 2.5 to 4.0s= 0m/s </span>

<span>average velocity from 0 to 4.0s= (4+0)/4 </span>
<span>= 1m/s </span>

<span>c. average velocity from 1.0 to 4.0s= (4/3)m/s </span>

<span>average velocity from 4.0 to 5.0s= 2/1 </span>
<span>= 2.0m/s </span>

<span>average velocity from 1.0 to 5.0s= ((4/3)+2)/4 </span>
<span>= (5/6)m/s </span>

<span>d. average velocity from 0 to 4.0s= 1.0m/s </span>

<span>average velocity from 4.0 to 5.0s= 2.0m/s </span>

<span>average velocity from 0 to 5.0s= (1.0+2.0)/5 </span>
<span>= (3/5)m/s </span>
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An article presents voltage measurements for a sample of 66 industrial networks in Estonia. Assume the rated voltage for these n
kramer

Answer:

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 232 V

Sample mean, \bar{x} = 231.5 V

Sample size, n = 66

Sample standard deviation, s = 2.19 V

Alpha, α = 0.05

First, we design the null and the alternate hypothesis

H_{0}: \mu = 232\\H_A: \mu \neq 232

We use Two-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n-1}} } Putting all the values, we have

t_{stat} = \displaystyle\frac{231.5- 232}{\frac{2.19}{\sqrt{66}} } = -1.8548

Now,

t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = \pm 1.9971

Since,              

|t_{stat}| > |t_{critical}|

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

4 0
3 years ago
PLEASE HELP!!!!!!!!
vfiekz [6]

Answer:

about 78 years

Step-by-step explanation:

Population

y =ab^t  where a is the initial population and b is 1+the percent of increase  

    t is in years

y = 2000000(1+.04)^t

y = 2000000(1.04)^t

Food

y = a+bt   where a is the initial population and b is constant increase

    t is in years

b = .5 million = 500000

y = 4000000 +500000t

We need to set these equal and solve for t to determine when food shortage will occur

2000000(1.04)^t= 4000000 +500000t

Using graphing technology, (see attached graph  The y axis is in millions of years), where these two lines intersect is the year where food shortages start.

t≈78 years

8 0
3 years ago
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10(x – 9) &gt; -270<br> How do I do this ?
Ilia_Sergeevich [38]

Answer:

x > -18

Step-by-step explanation:

10 ( x - 9 ) > -270

Treat the inequality like an equation,

Distribute first:

10 ( x - 9 ) > - 270

10x - 90 > -270

Inverse operations:

10x - 90 > -270

      +90    +90

10x > -180

/10     /10

x > -18

4 0
3 years ago
If angle A B C is congruent to angle C B D find x.
madam [21]
X+1=4x-2
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x+3=4x
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3=3x
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3 years ago
What c-value makes the set of ratios equivalent. HELP ASAP
rosijanka [135]

Answer:

6 ---------> 2x : 48 = 3 : 12

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16 -------->  12 : 15 = x : 20

24 ------->  4 : 7  = x : 42

Step-by-step explanation:

3 0
2 years ago
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