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Anna007 [38]
3 years ago
9

A tennis player moves in a straight-line path as shown in the figure below. find her average velocity in the following time inte

rvals.
Mathematics
1 answer:
Andreyy893 years ago
4 0
To find the average velocity in a velocity-time graph at a particular interval, simply determine the gradient at that particular interval. 

<span>a. average velocity= 4/1 </span>
<span>= 4m/s </span>

<span>b. average velocity from 1 to 2.5s= 6/(2.5-1) </span>
<span>= 4m/s </span>

<span>average velocity from 2.5 to 4.0s= 0m/s </span>

<span>average velocity from 0 to 4.0s= (4+0)/4 </span>
<span>= 1m/s </span>

<span>c. average velocity from 1.0 to 4.0s= (4/3)m/s </span>

<span>average velocity from 4.0 to 5.0s= 2/1 </span>
<span>= 2.0m/s </span>

<span>average velocity from 1.0 to 5.0s= ((4/3)+2)/4 </span>
<span>= (5/6)m/s </span>

<span>d. average velocity from 0 to 4.0s= 1.0m/s </span>

<span>average velocity from 4.0 to 5.0s= 2.0m/s </span>

<span>average velocity from 0 to 5.0s= (1.0+2.0)/5 </span>
<span>= (3/5)m/s </span>
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Which of the following lines is perpendicular to the x-axis and contains the point (-11.4, 12.8)
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The line x = -11.4 is perpendicular to the x-axis and contains point

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Step-by-step explanation:

Let us revise the equations of the vertical lines and horizontal lines

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  • The x-coordinates of all points lie on the line are equal
  • The equation of the vertical line basses through point (a , b) is x = a
  • The horizontal line is a line parallel to x-axis
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∵ The line is perpendicular to the x-axis

∴ The line is a vertical line

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   of any point lies on the line

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∴ a = -11.4

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Learn more:

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