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3 years ago

Find the product. 3(m + n) 3m + 3n 3mn 3m-n

Mathematics

1 answer:

Pani-rosa [81]3 years ago

7 0

That is not right. Is that all your work on the bottom?

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-5/12+5/8 what is the answer to this

enot [183]

Answer:

5/24

Step-by-step explanation:

-5/12+5/8

-10/24+15/24

5/24

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3 years ago

Please help on this question

son4ous [18]

The perimeter would be 48 feet

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3 years ago

The lifespan of a guinea pig is 8 years shorter than the lifespan of a puma. Write a subtraction equation that you could use to

KiRa [710]

Answer: p-8

Step-by-step explanation:first thins problem is impossible without knowing the lifespan of a puma. But if you knew it oh let’s say it was 20 you would subtract the puma by 8.

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3 years ago

Select the correct answer.

shutvik [7]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

If y=e5t is a solution to the differential equation

a_sh-v [17]

Answer:

k = 30, $y(t) = C_1e^{5t}+C_2e^{6t}$

Step-by-step explanation:

Since $y=e^{5t}$ is a solution, then it must satisfy the differential equation. So, we calculate the derivatives and replace the value in the equation. We have that

$\frac{d^2y}{dt^2} = 25 e^{5t},\frac{dy}{dt} = 5e^{5t}$

Then, replacing the derivatives in the equation we have:

$25e^{5t}-11(5)e^{5t}+ke^{5t}=0 e^{5t}(25-55+k) =0$

Since $e^{5t}$ is a positive function, we have that

$25-55+k = 0 \rightarrow k = 30$ .

Now, consider a general solution $y(t) = Ae^{rt}, A \in \mathbb{R}$ , then, by calculating the derivatives and replacing them in the equation, we get

$Ae^{rt}(r^2-11r+30)=0$

We already know that r=5 is a solution of the equation, then we can divide the polynomial by the factor (r-5) to the get the other solution. If we do so, we get that (r-6)=0. So the other solution is r=6.

Therefore, the general solution is

$y(t) = C_1e^{5t}+C_2e^{6t}$

8 0

3 years ago