Question:
Find the value of the letter in each of the following and give reasons for the steps involved:
1 2 A
+ 6 A B =
A 0 9
Answer:
128 + 681 = 809
Step-by-step explanation:
Here, let's use the general form of numbers where any letter must represent one value and each digit must be represented by just one letter.
Take the following:
A = 8
B = 1
Thus, A +B = 8 + 1 = 9
Also add:
8 + 2 = 10
In general form, tens digit is zero and the 1 is carried over.
I.e, A = 1 + 6 + 1 = 8
We can now see that,
A = 8
B = 1
Therefore,
1 2 A
+ 6 A B =
A 0 9
Will be written as:
128 + 681 = 809
Quartic => polynolial degree 4, i.e. the highest exponent of the variable is 4
trinomial=> three terms
leading coefficient = the coefficient in front of the term with the highest exponent.
standard form=> ax^4 + bx^3 + c^2 + dx + e
Solution:
2x^4 + x^3 + 0x^2 + 0x + 30
which is equal to 2x^4 + x^3 + 30: this is a quartic trinomial with leading coefficient 2, written in standard form.
Answer:7
Step-by-step explanation:
Remember,
PEMDAS
Begin by 3 / 1/3 = 1
1+1=2
9-2 = 7
Answer:
256 miles
Step-by-step explanation:
The Pythagoras theorem is a² = b² + c² where a is the hypotenuse or longest side
To find the shorter side, the equation is rearranged so c² = a² - b² (whether it is b or c doesn't matter)
so √377² - 277² = 255.7342371
