Answer:
A
Step-by-step explanation:
It because I think it is the correct
Answer:
Step-by-step explanation:
Here,
y
∝
x
⇒
y
=
k
x
where k is constant.
⇒
1
=
k
.2
[put y =1,x=2]
⇒
k
=
1
2
Again, y = kx
⇒
y
=
1
2
×
4
[put x = 4]
⇒
Y
=
2
Answer:
y
=
2
Answer:
Probability that the average mileage of the fleet is greater than 30.7 mpg is 0.7454.
Step-by-step explanation:
We are given that a certain car model has a mean gas mileage of 31 miles per gallon (mpg) with a standard deviation 3 mpg.
A pizza delivery company buys 43 of these cars.
<em>Let </em>
<em> = sample average mileage of the fleet </em>
<em />
The z-score probability distribution of sample average is given by;
Z =
~ N(0,1)
where,
= mean gas mileage = 31 miles per gallon (mpg)
= standard deviation = 3 mpg
n = sample of cars = 43
So, probability that the average mileage of the fleet is greater than 30.7 mpg is given by = P(
<em> </em>> 30.7 mpg)
P(
<em> </em>> 30.7 mpg) = P(
>
) = P(Z > -0.66) = P(Z < 0.66)
= 0.7454
<em>Because in z table area of P(Z > -x) is same as area of P(Z < x). Also, the above probability is calculated using z table by looking at value of x = 0.66 in the z table which have an area of 0.7454.
</em>
Therefore, probability that the average mileage of the fleet is greater than 30.7 mpg is 0.7454.
Answer:
2nd option, rectangle B
Step-by-step explanation:
After reflexion, the figure will be at the left side of x=-5