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Phoenix [80]
3 years ago
12

Which number line represents the solution to 2.5-1.2x<6.5 - 3.2x?

Mathematics
1 answer:
jarptica [38.1K]3 years ago
8 0

Answer:

Step-by-step explanation:

subtract 2.5 and add 3.2x to both sides

2.0x < 4.0

x < 2

Not sure which of your choices reflects that solution. They're kinda hard to read

mooch
2 years ago
answer c
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The mean of 15 numbers is y.If each of the number is increased by 30, find the increase of the new mean in terms of y.The answer
dusya [7]

Answer:

y+30

Step-by-step explanation:

the sum of the numbers is 15y

the new sum after increase each number by 30 is 15y+450

the new mean 15y+450/15

= y+30

4 0
2 years ago
Simplify two to the fifth power over three to the second power
Savatey [412]
[/tex]\frac{32}{9}
This changes to a mix fraction
3 [tex] \frac{5}{9}
8 0
3 years ago
The two triangles are similar. What is the value of x?
Ghella [55]

Answer:

x=5

Step-by-step explanation:

We can write ratios to help us solve

4x            12 +3

---------- = ------------

3x+1                 12

Using cross products

4x*12 = (3x+1) * (15)

48x = 45x +15

Subtract 45x from each side

3x =15

Divide by 3

3x/3 =15/3

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5 0
2 years ago
I need help asap!!!!!
Svetllana [295]
Answer: 130

In order to solve for <4, you need to know that supplementary angles add up to 180°. 
<3 = 50
180 - 50
130

**For future questions**
1. The sum of the interior angles of a triangle is 180°
2. Alternate interior angles are congruent
3. The exterior angle of a triangle is the sum of the nonadjacent interior angles

See attachment below. 

4 0
3 years ago
Find the equation of the axis of symmetry and the coordinates of vertex of the functions =2x^2+4x-3
SVEN [57.7K]
Hello,

Find the equation of the axis of symmetry is like find the maximum or minimum point of this function.

f(x)=2x^2+4x-3\\\\\alpha=-\dfrac{b}{2a}=-\dfrac{4}{4}=-1\\\\

The equation of the axis of symmetry is then :   x=-1

\beta=f(\alpha)=2(-1)^2+4(-1)-3=2-4-3=-5

Coordinates of vertex :   (\alpha,\beta)=(-1;-5)
8 0
3 years ago
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