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3 years ago

Reflect figure E across the x-axis and then reflect across the y-axis. What is the resulting figure?

Mathematics

1 answer:

Andreas93 [3]3 years ago

3 0

Answer:

2nd option, rectangle B

Step-by-step explanation:

After reflexion, the figure will be at the left side of x=-5

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Estimate the product. Then find the actual product.

Artist 52 [7]

Answer:

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Step-by-step explanation:

483*9.2=4443.6 actual product

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2 years ago

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Use the quadratic formula to find both solutions to the quadratic equation given below. 2x^2+3x-5=0

Alisiya [41]

Answer:

x=1 and x= -2.5

Step-by-step explanation:

✯Hello✯

The quadratic formula is x=-b+-(sqrt)b^2-4ac/2a

A = 2

B= 3

C = -5

PLUG THESE VALUES INTO THE QUADRATIC FORMULA

we can see that x=1 and x= -2.5

❤Gianna❤

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3 years ago

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Please help, ASAP!!

babymother [125]

Answer:

The answer should be x ≤ 5

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2 years ago

No cap got a brain fart need help just gotta find x

VladimirAG [237]

Answer:

ok did you really just say brain fart I'm dying I cant stop laughing

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2 years ago

Solve the equation on the interval [0, 2pi): 12cos^2 x-9=0<br><br><br> What to do?

siniylev [52]

Answer:

$\large\boxed{x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}}$

Step-by-step explanation:

$12\cos^2x-9=0\qquad\text{add 9 to both sides}\\\\12\cos^2x=9\qquad\text{divide both sides by 12}\\\\\cos^2x=\dfrac{9}{12}\\\\\cos^2x=\dfrac{9:3}{12:3}\\\\\cos^2x=\dfrac{3}{4}\to\cos x=\pm\sqrt{\dfrac{3}{4}}\\\\\cos x=\pm\dfrac{\sqrt3}{2}\\\\\text{Look at the picture}\\\\x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}$

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3 years ago