Answer:
I gave you most of the answer. I'll let you check my work and find the point using the solution.
Step-by-step explanation:
The first thing we do is we divide by negative one in the first equation to get
y = -x.
-3x + 3y = -36
Plug in y = -x and get
-3x + 3(-x) = -36
= -3x - 3x = -36
This equals -6x = -36
divide both sides by -6 and you get 6. 6 is your x value
Plug 6 back in to the second equation.
-3x + 3y = -36
-3(6) + 3y = -36
-18 + 3y = -36
3y = -18
y = -6
27x^2-81x-9x+27 In this case, just in your mind multiply 27 (coefficient of x^2) by the constant value 27(the end value of the quadratic trinomial). Then find factors that give you the value -90 when you add and 729 (27*27) when you multiply.
Factorise the values
27x( x-3)-9(x-3)
Which will give you
(27x-9)(x-3)
Answer:
1320 ways
Step-by-step explanation:
Here we have a situation where 3 ribbons will be awarded to 3 of the 12 contestants. We can use the permutation formula, because the order of awarding the ribbons matters.
The permutation formula is:
n = 12
k = 3
Now that we have our variables, let's plug them into the formula.
So there are 1320 different ways that the contestants will be awarded.
