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3 years ago

In circle E with m DEF 36 and DE = 3 units find area of

Mathematics

1 answer:

deff fn [24]3 years ago

4 0

Answer:

A ≈ 2.83 units²

Step-by-step explanation:

The area (A) of the sector is calculated as

A = area of circle × fraction of circle

= πr² × $\frac{36}{360}$

= π × 3² × $\frac{1}{10}$

= $\frac{9\pi }{10}$

≈ 2.83 units² ( to the nearest hundredth )

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PLS AWNSER NOW

sattari [20]

Answer:

600

Step-by-step explanation:

2000/10=200. 200x3=600

4 0

2 years ago

Use the given information to find the exact value of the trigonometric function

eimsori [14]

$\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}$

Half Angle Formula

$\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}$ $\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}$ $\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}$ $\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\ \\ \end{gathered}$

Answer:

$\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}$

Checking:

$\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{ (3rd quadrant)} \end{gathered}$

Also,

$\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}$

The answer is none of the choices

7 0

11 months ago

4x-3+x=7x-3 solve x and show work easy to undertand please. Really appreciate it ^^

nalin [4]

Answer: x = 0

Step-by-step explanation:

4x − 3 + x = 7x − 3

Step 1: Simplify both sides of the equation.

4x − 3 + x = 7x − 3

4x + −3 + x = 7x + −3

(4x + x) + (−3) = 7x − 3(Combine Like Terms)

5x + −3 = 7x − 3

5x − 3 = 7x − 3

Step 2: Subtract 7x from both sides.

5x − 3 − 7x = 7x − 3 − 7x

−2x − 3 = −3

Step 3: Add 3 to both sides.

−2x − 3 + 3 = −3 + 3

−2x = 0

Step 4: Divide both sides by -2.

-2x/-2 = 0/-2

x = 0

3 0

2 years ago

Read 2 more answers

Divide the following quantiles in the given ratio £100 1:3 £80 3:5 £250 2:3:5

goblinko [34]

Answer:

Step-by-step explanation:

£100

1:3

1+3=4

1/4×£100

=£25

3/4×£100

=£75

£80

3:5

3+5=8

3/8×£80

=£30

5/8×£80

=£50

£250

2:3:5

2+3+5=10

2/10×£250

=£50

3/10×£250

=£75

5/10×£250

=£125

6 0

3 years ago

I need help with these problems please

katovenus [111]

Answer:

1. Reflection

2. Dilation

3. Rotation

Step-by-step explanation:

Hey!

You can tell number one is a reflection because it didn’t change side or turn upside down or anything, it just flipped over to the other side.

You can tell number two is a dilation because it changes size.

You can tell number three is rotation because it rotated.

Hope this helps! :D

If you have any further questions, comment down below!

8 0

2 years ago