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Whitepunk [10]
3 years ago
11

a company installs 5000 light bulbs each with an average life of 500 hours and a deviation of 100 hours. find the percentage of

bulbs that can be expected to last the period of time specified assuming the data is normally distributed g
Mathematics
1 answer:
Andrei [34K]3 years ago
8 0

Answer:

Probability is 0

Step-by-step explanation:

The key information is that the data is normally distributed.

In a normal distribution, each individual value of hours has a probability equals to zero. It is a continuos distribution which is centered in the mean value, and where the expected value is the average.

As the distribution it is centered in the mean value, and it is symmetrical, then the probabilty of a bulb lasting more than the mean value is 0.5, and the probabilty of lasting less than avergare is 0.5 as well, but each individual valu is 0

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Factor 125x^3-1000. Show your work.
Salsk061 [2.6K]

The left term is (5x)³.

The right term is 10³.

So, you can use the formula for the factorization of the difference of cubes.

... a³ - b³ = (a-b)(a² +ab +b²)

Here, you have a=5x, b=10, so the factorization is

... 125x³ -1000 = (5x-10)(25x² +50x +100)

4 0
2 years ago
Five distinct numbers are randomly distributed to players numbers 1 through 5. Whenever two playerscompare their numbers, the on
ad-work [718]

Answer:

Observe that the first and the second player have equal probability to get any of number. Using the principle of that symmetry, we have that  

P(X=0)=\frac{1}{2}

<u>Event X = 1 </u>means that the first player has got greater number than the second player, but not than the third player. So, choose any three numbers out of five of them and say that the minimal number out of these three goes to the second player, mean number to the first one and the largest to the third one. Permute remaining two numbers on remaining two people. Hence

P(X=1)=\frac{1}{6}

<u>Event X = 2</u> means that the first player has got greater number than the second and the third player, but not than the fourth player. So, choose any four numbers out of five of them and say that the minimal number and the next minimal out of these four go to the second and the third player (and permute them), third number to the first one and the largest to the fourth player. Give remaining number to the last person. Hence

P(X=2)=\frac{1}{12}

<u>Event X = 3</u> means that the first player has got greater number than the second, the third, and the forth player, but not than the fifth player. So, permute these five numbers as follows: give the highest to the last person, the second highest to the first, and permute remaining numbers on the remaining people. Hence  

P(X=3)=\frac{1}{20}

<u>Event X = 4</u> means basically the first player has won all the battles i.e, he has got the greatest number. Hence

P(X=4)=\frac{1}{5}

7 0
3 years ago
Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts
shepuryov [24]

Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) y = arctan(t(lnt - 1) + C)

(c) y = -1/ln|0.09(t + 1)²/t|

Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

Integrate both sides

tany = t(lnt - 1) + C

y = arctan(t(lnt - 1) + C)

(c) (t² + t) dy/dt + y² = ty², y(1) = -1

(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

8 0
3 years ago
You will need 50% of a packet of pasta to make a meal for 4 people. How
skelet666 [1.2K]

you would use 1.5 packets, but that requires 2 packets.

1 packet in total would feed 8 people, and half of another would feed an extra 4. 4+8 = 12.

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Express the area of the entire rectangle.
Cloud [144]

Answer:

\huge\boxed{A=x^2+12x+35}

Step-by-step explanation:

The formula of an area of a rectangle:

A=lw

<em>l</em><em> - length</em>

<em>w</em><em> - width</em>

We have

l=x+7\\\\w=x+5

Substitute:

A=(x+7)(x+5)

Use FOIL <em>(a + b)(c + d) = ac + ad + bc + bd</em>

<em></em>A=(x)(x)+(x)(5)+(7)(x)+(7)(5)\\\\A=x^2+5x+7x+35<em></em>

combine like terms

A=x^2+(5x+7x)+35\\\\A=x^2+12x+35

7 0
3 years ago
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