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Whitepunk [10]
3 years ago
11

a company installs 5000 light bulbs each with an average life of 500 hours and a deviation of 100 hours. find the percentage of

bulbs that can be expected to last the period of time specified assuming the data is normally distributed g
Mathematics
1 answer:
Andrei [34K]3 years ago
8 0

Answer:

Probability is 0

Step-by-step explanation:

The key information is that the data is normally distributed.

In a normal distribution, each individual value of hours has a probability equals to zero. It is a continuos distribution which is centered in the mean value, and where the expected value is the average.

As the distribution it is centered in the mean value, and it is symmetrical, then the probabilty of a bulb lasting more than the mean value is 0.5, and the probabilty of lasting less than avergare is 0.5 as well, but each individual valu is 0

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Write the fraction in lowest terms.<br><br> 13/17
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The number of bacteria, B, in a refrigerated food is given by the function b(t) = 15t2 - 60t + 125, where t is the temperature o
Nimfa-mama [501]

Answer: b(t(h))=135h^2+180h+125


Step-by-step explanation:

Given: The number of bacteria, B, in a refrigerated food is given by the function  b(t)=15t^2-60t+125 , where t is the temperature of food in degrees Fahrenheit.

The function t(h)=3h+4 gives the temperature, t, of the food h hours after being removed from the refrigerator.

Now, the number bacteria in the food in h hours is given by:-

b(t(h))=15(3h+4)^2-60(3h+4)+125\\=15(9h^2+16+24h)-180h-240+125\\=135h^2+240+360h-180h-240+125\\=135h^2+180h+125

So, The number bacteria in the food in h hours is given by:

b(t(h))=135h^2+180h+125


4 0
3 years ago
The gas mileage for a certain vehicle can be approximated by m=−0.05x2+3.5x−49, where x is the speed of the vehicle in mph. Dete
Whitepunk [10]

Answer:

<h2>14mph</h2>

Step-by-step explanation:

Given the gas mileage for a certain vehicle modeled by the equation m=−0.05x²+3.5x−49 where x is the speed of the vehicle in mph. In order to determine the speed(s) at which the car gets 9 mpg, we will substitute the value of m = 9 into the modeled equation and calculate x as shown;

m = −0.05x²+3.5x−49

when m= 9

9 = −0.05x²+3.5x−49

−0.05x²+3.5x−49 = 9

0.05x²-3.5x+49 = -9

Multiplying through by 100

5x²+350x−4900 = 900

Dividing through by 5;

x²+70x−980 = 180

x²+70x−980 - 180 = 0

x²+70x−1160 = 0

Using the general formula to get x;

a = 1, b = 70, c = -1160

x = -70±√70²-4(1)(-1160)/2

x = -70±√4900+4640)/2

x = -70±(√4900+4640)/2

x = -70±√9540/2

x =  -70±97.7/2

x = -70+97.7/2

x = 27.7/2

x = 13.85mph

x ≈ 14 mph

Hence, the speed(s) at which the car gets 9 mpg to the nearest mph is 14mph

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