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butalik [34]
3 years ago
5

HELP WILL MARK BRAINLIEST TO BEST ANSWER!!!!!!!! I NEED ASAP

Mathematics
1 answer:
Bond [772]3 years ago
4 0
Answer is B

Find perimeter then divide by 3 (because price is per 3 meters) then times by 500 to get the answer
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Find the percent increase. Round to the nearest percent. From 11 friends to 18 friends
ozzi

Answer:

its 63.6% is the closest but rounded up its 64%

Step-by-step explanation:

5 0
3 years ago
Can someone help me please
Westkost [7]

Answer:

  10.  20.9°

  11.  73.2°

Step-by-step explanation:

The inverse sine function is used to find the angle from its sine value.

<h3>10.</h3>

In each case, the equation is of the form ...

  a/sin(x) = b/c

Multiplying both sides by c/b·sin(x), we find the solution is ...

  sin(x) = ac/b . . . . . find sin(x)

  x = arcsin(ac/b) . . . . . find the corresponding angle

For the given values a=7.2, b=13, c=sin(40°), we have ...

  x = arcsin(7.2sin(40°)/13) ≈ 20.9°

<h3>11.</h3>

For the given values a=6.53, b=√40, c=sin(68°), we have ...

  x = arcsin(6.53sin(68°)/√40) ≈ 73.2°

5 0
2 years ago
RCTCT00; assignments/teacher/Kaid_250867773793737153732659/class/4644345915342848
NikAS [45]

Answer:

See picture for the answer and steps!

Step-by-step explanation:

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3 years ago
Find the measure of angle F if measure angle D equals 88
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3 years ago
Read 2 more answers
The time between telephone calls to a cable television service call center follows an exponential distribution with a mean of 1.
Ulleksa [173]

Answer:

0.52763 is the probability that the time between the next two calls will be 54 seconds or​ less.

0.19285 is the probability that the time between the next two calls will be greater than 118.5 ​seconds.

Step-by-step explanation:

We are given the following information in the question:

The time between telephone calls to a cable television service call center follows an exponential distribution with a mean of 1.2 minutes.

The distribution function can be written as:

f(x) = \lambda e^{-\lambda x}\\\text{where lambda is the parameter}\\\\\text{Mean} = \mu = \displaystyle\frac{1}{\lambda}\\\\\Rightarrow 1.2 = \frac{1}{\lambda}\\\\\lambda = 0.84 \\f(x) = 0.84 e^{0.84 x}

The probability for exponential distribution is given as:

P( x \leq a) = 1 - e^{\frac{-a}{\mu}}\\\\P(a \leq x \leq b) = e^{\frac{-a}{\mu} -\frac{-b}{\mu}}

a) P( time between the next two calls will be 54 seconds or​ less)

P( x \leq 0.9)\\= 1 - e^{\frac{\frac{-54}{60}}{1.2}} = 0.52763

0.52763 is the probability that the time between the next two calls will be 54 seconds or​ less.

b) P(time between the next two calls will be greater than 118.5 ​seconds)

p( x > \frac{118.5}{60}) = P(x > 1.975)\\\\ = 1 - P(x \leq 1.975) \\\\= 1 -1+ e^{\frac{-1.975}{1.2}}\\\\= 0.19285

0.19285 is the probability that the time between the next two calls will be greater than 118.5 ​seconds.

6 0
3 years ago
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