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bearhunter [10]
3 years ago
12

Fractions greater than 1/2 all of them

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
6 0
There are a lot of them
3/4 , 2/3 any fraction greater than .5 will fall in this category.
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Solve the following inequality for x, then describe what the graph would look like.
Alex17521 [72]

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

Inequality Form:  

x≤−3

Interval Notation: ( − ∞ , − 3 ]

4 0
3 years ago
Is the data set "the colors of the leaves on a branch" quantitative or qualitative? If it is quantitative, is it discrete or con
Mice21 [21]

Answer:

Option C. qualitative

Step-by-step explanation:

A qualitative variable is the type of variable that can't be numerically expressed but can be categorized. The colors of the leaves on a branch can be categorized as green, yellow and orange etc. Thus, the colors of the leaves is a qualitative variable. So, the correct option is C.

6 0
3 years ago
Read 2 more answers
If 5 years ago nina was twice as old as sam, how soon from now will she be 1.5 times as old as sam? if x is sam's age 5 years ag
Anna35 [415]
I hope this helps you

7 0
3 years ago
A 3-card poker hand is dealt at random from a standard 52-card deck. what is the total number of possible hands
Stells [14]
This depends on the number of players or hands dealt. If its one, it would be 17 (17.3 repeating to be exact),if its more than 2, thne just do 52/x and then divide that number by 3.
7 0
3 years ago
The concentration of a drug in the bloodstream C(t) at any time t, in hours, is described by the equationC(t)=100t/t^2+25where t
alisha [4.7K]

Answer:

It will take 5 hours until it reaches its maximum concentration.

Step-by-step explanation:

The maximum concentration will happen in t hours. t is found when

C'(t) = 0

In this problem

C(t) = \frac{100t}{t^{2} + 25}

Applying the quotient derivative formula

C'(t) = \frac{(100t)'(t^{2} + 25) - (t^{2} + 25)'(100t)}{(t^{2} + 25)^{2}}

C'(t) = \frac{100t^{2} + 2500 - 200t^{2}}{(t^{2} + 25)^{2}}

C'(t) = \frac{-100t^{2} + 2500}{(t^{2} + 25)^{2}}

A fraction is equal to zero when the numerator is 0. So

-100t^{2} + 2500 = 0

100t^{2} = 2500

t^{2} = 25

t = \pm \sqrt{25}

t = \pm 5

We use only positive value.

It will take 5 hours until it reaches its maximum concentration.

4 0
3 years ago
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