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bearhunter [10]
4 years ago
12

Fractions greater than 1/2 all of them

Mathematics
1 answer:
Lera25 [3.4K]4 years ago
6 0
There are a lot of them
3/4 , 2/3 any fraction greater than .5 will fall in this category.
You might be interested in
Need help ASAP
horrorfan [7]

Answer:

39 cm

Step-by-step explanation:

using the x component go find 12 cm width and follow the line up until it intersects the graph. then follow that point left to estimate the height at that point to estimate 37.5 but more accurately you can use the given equation y=3.25x and plug in your x of 12 to get y=39

6 0
3 years ago
Which numbers will produce a rational number when multiplied by 1/5
labwork [276]
A rational number times a rational number=rational numberan irrational number times a rational number=irrational number
remember, a rational number is a number that can be written as a/b where a and b are integers and b≠0


A is irrational because the pattern doesn't repeatb is irrational because it's a crazy square rootC is irrationalD is not irrational, it is a fraction 

answer is D

 
3 0
3 years ago
(3x/2)^4 any answers
Anika [276]

\bf \left( \cfrac{3x}{2} \right)^4\implies \left( \cfrac{(3x)^4}{2^4} \right)\implies \left( \cfrac{3^4x^4}{2^4} \right)\implies \cfrac{81x^4}{16}

6 0
3 years ago
Read 2 more answers
Somebody please help me with this !!!
Damm [24]

Step-by-step explanation:

Case 1 :

3x + 2y = 6 \\ 4x + y = 2 \\ 3x = 6 - 2y \\ x =  \frac{6 - 2y}{3}  = \\ x = 2 -  \frac{2y}{3}  \\ 4(2 -  \frac{2y}{3} ) + y = 2 \\ 8 -  \frac{8y}{3}  + y = 2 \\  - 1.67y =  - 6 \\

y = 3.59 \\ x = 2 -  \frac{2y}{3}  \\x =  2 -  \frac{2 \times 3.59}{3}  \\  \\ x =  - 0.39

Case 2 :

3x + 2y = 6 \\ 4x  -  y = 2 \\ x = 2 -  \frac{2y}{3}  \\ 4(2 -  \frac{2y}{3} ) - y = 2 \\ 8 -  \frac{8y}{3}  - y = 2 \\   - 3.67y=  - 6 \\ y = 1.63

x = 2 -  \frac{2y}{3}  \\ x = 2 -  \frac{2 \times 1.63}{3}  \\ x = 2 - 1.087 \\ x = 0.913

7 0
3 years ago
2x2 - 12x + 10<br>what are the roots​
Tcecarenko [31]

Answer:

5 & 1

Step-by-step explanation:

We can use the quadratic formula to solve this:

Quadratic Formula = \frac{-b+-\sqrt{b^2-4ac} }{2a}

So we will have 2 answers (roots).

a is the coefficient of x^2 (2)

b is the coefficient of x (-12)

c is the constant (10)

Now, substituting, we get:

x = \frac{-b+-\sqrt{b^2-4ac} }{2a}=\frac{12+-\sqrt{(-12)^2-4(2)(10)} }{2(2)}=\frac{12+-\sqrt{64} }{4}=\frac{12+-8}{4}=\frac{12+-8}{4}=5,1

Hence the roots are 5 & 1

4 0
3 years ago
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