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2 years ago

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Tickets for a play cost $4 for each child and $8 for each adult. If there are only 20 children's tickets sold, which of the foll

owing equations could model how much total money y is made in ticket sales?

1 answer:

dimaraw [331]2 years ago

8 0

What are the answer choices?

You might be interested in

Plums cost $0.77 per pound Mangoes cost $1.32 per pound Write an expression that can be used to find the cost of buying p pounds

marissa [1.9K]

Answer:

The graphs below show the cost y of buying x pounds of fruit. One graph shows the cost of buying x pounds of peaches, and the other shows the cost of buying x pounds of plums.

Which kind of fruit costs more per pound? Explain.

Bananas cost less per pound than peaches or plums. Draw a line alongside the other graphs that might represent the cost y of buying x pounds of bananas.

IM Commentary

This task allows students to reason about the relative costs per pound of the two fruits without actually knowing what the costs are. Students who find this difficult may add a scale to the graph and reason about the meanings of the ordered pairs. Comparing the two approaches in a class discussion can be a profitable way to help students make sense of slope.

Solutions

Solution: Slope as Unit Rate

The graph that represents the cost of x pounds of peaches is steeper, so it must have a larger slope. The slope can be interpreted as the unit rate; in this case it tells you the cost of a single pound of fruit.

Since the slope for the peach graph is greater than the slope of the plum graph, the cost of a pound of peaches is greater than the cost of a pound of plums.

For b, students should realize that the cost per pound of bananas will be represented by a slope that is less than either of the other two, and draw a line through the origin labeled "Bananas" and lying below both of the other graphs.

Solution: Adding a scale to the graph

Students who prefer to work with specific numbers can approach this problem by sketching in a scale on the x-axis and y-axis. For example, if they decided that a pound of peaches might cost a dollar, then they might plot the point (1,1) on the line labeled "Peaches", then fill out the rest of the scale accordingly. They could then read off the cost of a pound of plums and see that it is less than for peaches.

For the second question, they could choose any price per pound b for bananas that is less than the one they read off for plums, and then draw a line from the origin through the point (b, 1), and label it "Bananas".

4 0

3 years ago

Solve:<br> -8(x - 3) - 4x < 108

Rainbow [258]

Step-by-step explanation:-8x+24-4x<108

108-24

-12x<84

x<7

7 0

3 years ago

Solve the system of equations below algebraically <br> 2x+3y=6 and -5x+2y=4

Charra [1.4K]

Steps
I’m using elimination so I’m trying to get rid of y
To do that I multiply the first equation by 2 and the second by -3. Then solve
4x + 6x = 12
15x + -6x = -12
—————————
19x + 0 = 0
Divid by 19 to get x to one side. 0/19 is 0 so
X= 0
Plug that into an equation so 0 + 3y = 6
Divid by 3 and y = 2
Answer x = 0 y = 2

7 0

3 years ago

Please tell me the final answer and how you got it.

dem82 [27]

It is 484 m^2 ,to my understanding!

5 0

3 years ago

Identify the lower class limits, upper class limits, class width, class midpoints, and class boundaries for the given freque

maw [93]

Answer:

The number of individuals included in the summary is 146.

Step-by-step explanation:

The frequency distribution table provided is as follows:

Class Intervals Frequency

100 - 199 24

200 - 299 90

300 - 399 27

400 - 499 1

500 - 599 4

The lower class limit it the smallest value of each class interval.

Lower class limit = {100, 200, 300, 400, 500}

The upper class limit it the highest value of each class interval.

Upper class limit = {199, 299, 399, 499, 599}

The lower class boundaries are the lower class limits decreased by 0.5 and the upper class boundaries are the upper class limits increased by 0.5.

Class boundaries:

99.5 - 199.5

199.5 - 299.5

299.5 - 399.5

399.5 - 499.5

499.5 - 599.5

The class width is the difference between the class boundaries of each class.

Class width = 199.5 - 99.5 = 100

So, the class width is 100.

The midpoints of a class is the average value of the boundaries of a class.

$\text{Midpoint}_{100-199}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\$

$=\frac{99.5+199.5}{2}\\\\=149.5$

$\text{Midpoint}_{200-299}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\$

$=\frac{199.5+299.5}{2}\\\\=249.5$

$\text{Midpoint}_{300-399}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\$

$=\frac{299.5+399.5}{2}\\\\=349.5$

$\text{Midpoint}_{400-499}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\$

$=\frac{399.5+499.5}{2}\\\\=449.5$

$\text{Midpoint}_{500-599}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\$

$=\frac{499.5+599.5}{2}\\\\=549.5$

The number of individuals included in the summary is the sum of all frequencies.

$\text{Number of Individuals}=24 + 90 + 27 + 1 + 4=146$

Thus, the number of individuals included in the summary is 146.

3 0

3 years ago

Read 2 more answers