To effectively determine the correct answer, it would be helpful to write this into an algebraic expression. We let x as the number. We do as follows:
<span>Four times the square of a certain number increased by 6 times the number equals 108.
4x^2 + 6x = 108
The numbers can be either of the following since the equation generated was a quadratic equation which has two roots.
x = 4.5
x = -6 </span>
R = rides
S = sodas
6R + 3S = $21.75 —> -12R - 6S = -43.5
10R + 6S = $39.50–>10R + 6S = 39.5
Multiplying Justin’s whole equation by -2 will bring out the 6S’, so we can focus on the cost of one ride.
-2R = -4
Divide both sides by -2
So for one ride, it would cost $2.
To find the cost for one soda, we plug in the cost for a ride.
6(2) + 3S = $21.75
12 + 3S = $21.75
3S = $9.75
So for one soda, it would cost $3.25.
Answer:
221
Step-by-step explanation:
Day 8 is the first day of the second week.
Day 21 is the last day of week 3.
We need to know the n umber of bicycles made from t = 1 to t = 3
The function is b(t) = 110 + 0.5t^2 - 0.9t, where t is in weeks.
We need to integrate the function with the limits of 1 to 3.
Answer: 221
Answer:
(a-b, c)
Step-by-step explanation:
The midpoints of the two diagonals are the same, so we have ...
(P + (-a, 0))/2 = (O +(-b, c))/2
Multiplying by 2 and subtracting (-a, 0), we get ...
P = (0, 0) +(-b, c) -(-a, 0)
P = (a-b, c)
