With this question you can imagine that you have a 6 cm tall cylindrical container and you take a piece of paper that is 4 cm by 6 cm and wrap it around the cylinder, then take the sheet of paper off whilst maintaining its shape - the paper will form the shape of a cylinder (without a top and bottom) but the two dimensional shape enclosed would be a circle and the area of this circle is what the question is asking.
Now given that the cylinder is 6 cm tall you can assume that the width of the sheet of paper that you would be wrapping around it would also be 6 cm tall and thus the length of that paper would be 4 cm (we are given the dimensions of the sheet as 4 cm x 6 cm) - this length is equal to the circumference of the circle that forms the base of the cylinder:
C = 2πr
4 = 2πr
r = 2/π
Now that we know the radius of the circle we can find its area:
A = πr^2
A = π*(2/π)^2
= 4/π
= 1.27 cm^2 (to two decimal places)
Basically with these questions you should always try to imagine them in a practical situation, it makes it a lot easier in the long run.
Answer:
D
Step-by-step explanation:
it isnt equilateral or equiangular, or a regular polygon
Answer:
3
Step-by-step explanation:
Answer:
8 seconds
Step-by-step explanation:
lets first start by plugging in 1024 into initial height
h(t) = -16t^2 + 1024
I would find a Greatest Common Factor (GCF) first
-16(t^2 - 64) If this is new just think that if you multiply -16 by t squared and -64 you will come back to the original equation
But now we notice that T squared -64 can be factored with the difference of perfect squared method
so we will get -16(t-8)(t+8)
So to get the answers we will set everything equal to 0
-16t =0
t =0 this is the time that the penny was thrown
t-8 = 0
t = 8 the is the time the penny hit the ground
t+8 =0
t= -8 This is an extraneous solution or a solution that doesn't make sense so we just disregard the solution.
