Answer:
ASA
Step-by-step explanation:
In given triangle
Line BC = Line QR
Angle ABC = Angle PQR
Angle ACB = Angle PRQ
Computation:
Angle ABC = Angle PQR (Angle)
Line BC = Line QR (Side)
Angle ACB = Angle PRQ (Angle)
So,
ΔABC ≅ ΔPQR
By Angle Side Angle property
ASA
Answer:
mcdonalds
Step-by-step explanation:
Answer:
y + 3 = 10/11(x + 3)
Step-by-step explanation:
Given the points (-3, -3) and (8, 7), we can use these coordinates to solve for the slope of the line using the formula:

Let (x1, y1) = (-3, -3)
(x2, y2) = (8, 7)
Substitute these values into the slope formula:

Thus, slope (m) = 10/11.
Next, using the slope (m) = 10/11, and one of the given points (-3, -3), we'll substitute these values into the point-slope form:
y - y1 = m(x - x1)
Let (x1, y1) = (-3, -3)
m = 10/11
y - y1 = m(x - x1)
y - (-3) = 10/11[x - (-3)]
Simplify:
y + 3 = 10/11(x + 3) this is the point-slope form.
Mercury travels a distance of 153 461 500 kilometers on its orbit.
<h3>How much distance did Mercury travel on its orbit?</h3>
The statement indicates that Mercury has a <em>circular</em> orbit and indicates the <em>central</em> angle covered by translation. The distance traveled is found by definition of <em>circular</em> arc:
s = (2.65 rad) · (57 910 000 km)
s = 153 461 500 km
Please notice that the radius of translation is the distance from the Sun to Mercury.
Mercury travels a distance of 153 461 500 kilometers on its orbit.
To learn more on circular arcs: brainly.com/question/11329794
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