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Vikentia [17]
3 years ago
13

The length of the base of a right triangle is twice the height. If the height is ten meters, find the area of the right triangle

.
A) 20 m2
B) 60 m2
C) 100 m2
D) 200 m2
Mathematics
1 answer:
Ber [7]3 years ago
4 0

Answer:

the answer is C... 100 m2

Step-by-step explanatii just took the test and it was right. the base would be 20 and the height would be 10. from there you just you the formula for area of a right triangle.

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Pls help. What is the appropriate congruent for these triangles
tekilochka [14]

Answer:

ASA

Step-by-step explanation:

In given triangle

Line BC = Line QR

Angle ABC = Angle PQR

Angle ACB = Angle PRQ

Computation:

Angle ABC = Angle PQR (Angle)

Line BC = Line QR (Side)

Angle ACB = Angle PRQ (Angle)

So,

ΔABC ≅ ΔPQR

By Angle Side Angle property

ASA

5 0
2 years ago
Which place offers a higher wage?
____ [38]

Answer:

mcdonalds

Step-by-step explanation:

6 0
3 years ago
A vending machine that serves coffee pours a varying amount of liquid into a cup with varying mass. Assume
bonufazy [111]

Answer:400

Step-by-step explanation:

7 0
3 years ago
Write the equation of the line that passes through the points (-3, -3) and (8,7).
Verizon [17]

Answer:

y + 3 = 10/11(x + 3)

Step-by-step explanation:

Given the points (-3, -3) and (8, 7), we can use these coordinates to solve for the slope of the line using the formula:

m = \frac{y2 - y1}{x2 - x1}

Let (x1, y1) = (-3, -3)

(x2, y2) = (8, 7)

Substitute these values into the slope formula:

m = \frac{y2 - y1}{x2 - x1} = \frac{7 - (-3)}{8 - (-3)} = \frac{10}{11}

Thus, slope (m) = 10/11.

Next, using the slope (m) = 10/11, and one of the given points (-3, -3), we'll substitute these values into the point-slope form:

y - y1 = m(x - x1)

Let (x1, y1) = (-3, -3)

m = 10/11

y - y1 = m(x - x1)

y - (-3) = 10/11[x - (-3)]

Simplify:

y + 3 = 10/11(x + 3) this is the point-slope form.

3 0
3 years ago
The distance from the Sun to Mercury is approximately 57910000 km.
Tpy6a [65]

Mercury travels a distance of 153 461 500 kilometers on its orbit.

<h3>How much distance did Mercury travel on its orbit?</h3>

The statement indicates that Mercury has a <em>circular</em> orbit and indicates the <em>central</em> angle covered by translation. The distance traveled is found by definition of <em>circular</em> arc:

s = (2.65 rad) · (57 910 000 km)

s = 153 461 500 km

Please notice that the radius of translation is the distance from the Sun to Mercury.

Mercury travels a distance of 153 461 500 kilometers on its orbit.

To learn more on circular arcs: brainly.com/question/11329794

#SPJ1

6 0
2 years ago
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