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Vikentia [17]
3 years ago
13

The length of the base of a right triangle is twice the height. If the height is ten meters, find the area of the right triangle

.
A) 20 m2
B) 60 m2
C) 100 m2
D) 200 m2
Mathematics
1 answer:
Ber [7]3 years ago
4 0

Answer:

the answer is C... 100 m2

Step-by-step explanatii just took the test and it was right. the base would be 20 and the height would be 10. from there you just you the formula for area of a right triangle.

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A 12 ft ladder is leaning against a wall with an angle of elevation of 31.2 degrees. How high up the wall will the ladder reach?
Tom [10]

Answer:

12/sin90'=b/sin67'

12sin67'=bsin90'

b=12sin67/sin90'

Step-by-step explanation:

sister ,we can use the law of sines. since we have the angle of elevation and assume the wall makes a right  angle with the ground, our angle opposite the ground is 180-[90+23=67

hope this is  helpful for you

8 0
2 years ago
Taylor was asked to solve the system of linear equations
yarga [219]
Id take a guess and say line 1 because the rest looks correct
4 0
3 years ago
The equation y = \large 1\frac{1}{2}x represents the number of cups of dried fruit, y, needed to make x pounds of granola. Deter
Natasha2012 [34]

Answer:

(1\frac{1}{2},1) - False

(4,6) - True

(18,12) -- False

(0,0) -- True

(2\frac{1}{2},3\frac{3}{4}) -- True

Step-by-step explanation:

The points are

(1\frac{1}{2},1) , (4,6), (18,12), (0,0) and (2\frac{1}{2},3\frac{3}{4}) ---- missing from the question

Given

y = 1\frac{1}{2}x

Required

Determine if each of the points would be on y = 1\frac{1}{2}x

To do this, we simply substitute the value of x and of each point in y = 1\frac{1}{2}x.

(a) (1\frac{1}{2},1)

In this case;

x = 1\frac{1}{2} and y = 1

y = 1\frac{1}{2}x becomes

y = 1\frac{1}{2} * 1\frac{1}{2}

y = \frac{3}{2} * \frac{3}{2}

y = \frac{9}{4}

y = 2\frac{1}{4}

<em>The point </em>(1\frac{1}{2},1)<em>  won't be on the graph because the corresponding value of y for </em>x = 1\frac{1}{2}<em> is </em>y = 2\frac{1}{4}<em></em>

(b) (4,6)

In this case;

x = 4

y = 6

y = 1\frac{1}{2}x becomes

y = 1\frac{1}{2} * 4

y = \frac{3}{2} * 4

y = \frac{3* 4}{2}

y = \frac{12}{2}

y = 6

<em>The point </em>(4,6)<em>  would be on the graph because the corresponding value of y for </em>x = 4 is y = 6

(c) (18,12)

In this case:

x = 18;y = 12

y = 1\frac{1}{2}x becomes

y = 1\frac{1}{2} * 18

y = \frac{3}{2} * 18

y = \frac{3* 18}{2}

y = \frac{54}{2}

y = 27

<em>The point </em>(18,12)<em>  wouldn't be on the graph because the corresponding value of y for </em>x = 18<em> is </em>y = 12<em></em>

(d) (0,0)

In this case;

x =0; y = 0

y = 1\frac{1}{2}x becomes

y = 1\frac{1}{2} * 0

y = 0

<em>The point </em>(0,0)<em>  would be on the graph because the corresponding value of y for </em>x = 0 is y = 0

(e) (2\frac{1}{2},3\frac{3}{4})

In this case:

x = 2\frac{1}{2}; y = 3\frac{3}{4}

y = 1\frac{1}{2}x becomes

y = 1\frac{1}{2} * 2\frac{1}{2}

y = \frac{3}{2} * \frac{5}{2}

y = \frac{15}{4}

y = 3\frac{3}{4}

<em>The point </em>(2\frac{1}{2},3\frac{3}{4}) <em>  would be on the graph because the corresponding value of y for </em>x = 2\frac{1}{2} is y = 3\frac{3}{4}

3 0
2 years ago
I don’t know how to do this. Can you help please help me ?
N76 [4]

Answer:

  • sin = -√3/2
  • cos = -1/2
  • tan = √3
  • sec = -2
  • csc = (-2/3)√3
  • cot = (√3)/3

Step-by-step explanation:

See the attached picture for a drawing of the angle and its terminal point coordinates. Those are (cos(4π/3), sin(4π/3)), so we have the following trig function values:

  sin(4π/3) = -√3/2

  cos(4π/3) = -1/2

  tan(4π/3) = sin/cos = √3

  sec(4π/3) = 1/cos = -2

  csc(4π/3) = 1/sin = -(2√3)/3

  cot(4π/3) = 1/tan = (√3)/3

_____

<em>Additional comment</em>

It helps to know that 1/√a = (√a)/a. This lets you write the ratios with a rational denominator in each case.

3 0
2 years ago
PLZZZZZZZZZZZZZZ HELP ME
ANTONII [103]

Answer:

316.41

Step-by-step explanation:

Because if you mutiply to find both volumes then add the volumes together you would get 316.41

3 0
3 years ago
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