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timurjin [86]
3 years ago
13

Answer question 1 and 2 thank you

Mathematics
1 answer:
GenaCL600 [577]3 years ago
8 0

Answer:

number 1: 3- $9:.00

2.4- $9.50

30- $120.00

number 2: m= 0s+4m

Step-by-step explanation:

I don't know for a fact if number 2 is correct.

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Please help me solve thisss (ASAP)
Ksju [112]
The sum of complementary angles is 90 degrees, thus

3x + 6 + 3x + 18 = 90
=> 6x + 24 = 90
=> 6x = 90 - 24 = 66
=> x = 66 / 6 = 11

=> m<A = 3(11) + 6 = 33 + 6 = 39 degrees.
8 0
3 years ago
I need some help with this question :/
Masteriza [31]
You have one of the answers correct. The fraction 4/8 is equal to 1/2

Other answers are: 5/10, 10/20, and 6/12

If you reduced each of those fractions, you'd get to 1/2. 

You can use a calculator to find that
4/8 = 0.5
1/2 = 0.5
5/10 = 0.5
10/20 = 0.5
6/12 = 0.5
All fractions mentioned lead to the same decimal value, so this confirms all of the fractions are equivalent to one another.
7 0
3 years ago
Read 2 more answers
What is bigger 1/3 or 3/5
raketka [301]

Method\ 1:

\dfrac{1}{3}=\dfrac{1\cdot5}{3\cdot5}=\dfrac{5}{15}\\\\\dfrac{3}{5}=\dfrac{3\cdot3}{5\cdot3}=\dfrac{9}{15}\\\\\dfrac{3}{15} < \dfrac{9}{15}\ therefore\ \dfrac{3}{5}\ is\ bigger


Method\ 2:

\dfrac{1}{3} < \dfrac{1}{2}=\dfrac{1.5}{3}\\\\\dfrac{3}{5} > \dfrac{1}{2}=\dfrac{2.5}{5}\\\\therefore\ \dfrac{3}{5}\ is\ bigger

6 0
3 years ago
S is the midpoint of RT. If RS = 7x-4 and ST = 5x+10, what is ST
Natali [406]

Answer: 45

Step-by-step explanation:

RS=ST\\\\7x-4=5x+10\\\\2x-4=10\\\\2x=14\\\\x=7\\\\\implies ST=5(7)+10=45

7 0
1 year ago
Help plzzzz! pre calc question
Mumz [18]

Answer:

\sum^{\infty}_0 {(-3)^n}

Step-by-step explanation:

Notice that the series: 1 - 3 + 9 - 27 +... clearly has powers of the factor 3 in its terms and it is also an alternate series (the terms alternate from positive to negative). The terms are positive for a_0, a_2, a_4, ... (even terms) , while the odd terms a_1, a_3, a_5, ... are negative. (so most likely there should be a factor   (-1) in the common ratio.

We can then represent it with the following summation expression:

\sum^{\infty}_0 {(-3)^n} given that each of its first four terms are:

a_0=(-3)^0=1\\a_1=(-3)^1=-3\\a_2=(-3)^2=(-3)*(-3)=9\\a_3=(-3)^3=(-3)*(-3)*(-3)=-27

7 0
3 years ago
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