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slavikrds [6]
3 years ago
9

PLEASE HELPP PRE CAL What is the greatest common factor of 8m^2, 4m, and 10m^4

Mathematics
2 answers:
luda_lava [24]3 years ago
4 0

Answer:

2m

Step-by-step explanation:

For m, I look for the greatest power of m that is in all of the expressions. Since the first has m^2, the second has m, and the third has m^4, the greatest power of m that is in all expressions is m.

For the number, I look for the greatest factor of 8, 4, and 10. A trick would be to look at the smallest number since the greatest common factor can only be less than or equal to the smallest number. So looking at 4, the factors are 1,2,4. 4 is not a common factor since it does not divide into 10, but 2 is so 2 is the greatest common numerical factor.

Combine 2 and m to get 2m.

Orlov [11]3 years ago
3 0

Answer:

2m

Step-by-step explanation:

8m² = 2×2×2×m×m

4m = 2×2×m

10m² = 2×5×m×m×m×m

Common are: 2×m = 2m

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There are 318 fiction books in the class library. The number of nonfiction books is 47 less than the number of fiction books. Ho
grigory [225]

Answer:

589 books in total

Step-by-step explanation:

fiction books= 381

non-fiction= 381-47= 271

total amount of books(ficton books and non-fiction books together)= 589 books in total

6 0
3 years ago
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Which expression is equivalent to: (x +9)(x+3)
labwork [276]

Answer:

c

Step-by-step explanation:

x*x=x^2

x*9=9x

x*3=3x

9x+3x=12x

9x3=27

x^2+12x+27

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3 years ago
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Brianna is going to a carnival that has games and rides. Each game costs $1.25 and each ride costs $3.75. Brianna spent $18.75 a
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Answer:

6 games and 3 rides

Step-by-step explanation:

Let the number of games Brianna played be x,

and the number of rides she went on be y.

Total cost for games= 1.25x

Total cost for rides= 3.75y

Since number of games is twice the number of rides,

x= 2y -----(1)

Total costs= cost of games +cost of rides

18.75= 1.25x +3.75y

Multiply the whole equation by 4 to remove the decimals:

75= 5x +15y

Simplify by dividing the whole equation by 5:

15 = x + 3y

Label the equation:

x +3y= 15 -----(2)

Although we can solve these 2 equations by substitution, since the question requires us to graphically solve, we have to graph 2 linear lines.

I will choose 3 points to plot on the graph for each equation:

x= 2y -----(1)

\begin{tabular}{|c|c|c|c|} \cline{1-4}x & 2(1) = 2&2(2) = 4&2(3) = 6\\ \cline{1-4}y & 1 &2&3\\ \cline{1-4}\end{tabular}

x +3y= 15 -----(2)

x= -3y +15

\begin{tabular}{|c|c|c|c|} \cline{1-4}x &  -3(1)+15= 12& -3(2)+15= 9& -3(3)+15= 6\\ \cline{1-4}y & 1 &2&3\\ \cline{1-4}\end{tabular}

Let's plot these points on a graph paper. Then, join them with a straight line for each straight line graph. Please see the attached picture for the graph.

From (1): y= ½x

From (2): 3y= 15 -x

y= 5 -⅓x

From the graph, the solution of the equation is (6,3). The solution is the point on the graph in which the 2 lines intersect.

x- coordinate: 6

y- coordinate: 3

Thus, Brianna played 6 games and went on 3 rides.

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x=48
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