Answer:
It would take 86.4 gallons of gas to go 1,836 miles.
Step-by-step explanation:
the situation can be explained by the equation 16x=340, where x is how many miles the car can go in one gallon. divide both sides by 16 to get that answer
x=340/16= 21.25
Now the other problem can be expressed by the equation 21.25y=1836, where y is the amount of gallons it would take to go 1,836 miles.
divide both sides by 21.25 to get the amount of gallons
y= 1836/ 21.25= 86.4.
If the sides are in the ratio of 11:16:24, it means that they are all multiples of a same number x, according to these factors.
So, the shorter side is 11x feet long, the middle one is 16x feet long, and the longest side is 24x feet long.
This means that the perimeter is
feet long. But we know that this is 510 feet, so we have
.
So, the three sides are 110, 160 and 240 feet long.
To find the area of a triangle knowing its three sides, you can use Heron's formula, which states that, if
is half the perimeter of the triangle whose sides are
, the area
is given by

In our case,
so the formula becomes

Answer:

Step-by-step explanation:
given
45 = 25m + b ( isolate the term in m by subtracting b from both sides )
45 - b = 25m ← divide both sides by 25
= m
Answer:
I think it would be 6800 square in because you just have to multiply 16 by 425.... Sorry if it is wrong
Step-by-step explanation:
Answer:
A) 154x89 _s2
s
Step-by-step explanation:
A) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
sA) 154x89 _s2
s