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masha68 [24]
4 years ago
14

The boxplots below show the flow of water, in m'/s, through a valve filter. The flow was recorded at 8 a.M. Each day for the las

t 5 months of the year. Flow of water a) In which of the five months was the 507 \m /S) median flow of water the highest? B) In which of the five months was the range of the flow of water the highest? C) Complete the statements below. (i) 25% of the results in November show a m'/s. Flow of water greater than (ii) Both the lower quartiles and medians were the same in the months of Dec. Month Nov. Aug.
Mathematics
1 answer:
Y_Kistochka [10]4 years ago
6 0

Answer:

25% of the results in Nov show a flow of water greater than 33m³/s

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Carlos found the area of the figure check his work and explain any errors​
Zanzabum

Answer:

The correct are is 5.5 cm².

Step-by-step explanation:

First of all, Carlos calciulated the are of the rectangle correctly, only the are unit is wrong, it should be 3 cm².

He made a mistake calculating the area of a the triangle: The area of a triangle can be calculated by multiplying the base by the height by \frac{1}{2}.

(Comment if you want a deeper explanation on where this comes from)

He mistakenly takes 4 cm for the height, but if you look carefully the height of the triangle in this case is 4 cm - 1.5 cm = 2.5 cm.

That gives \frac{1}{2} * 2 cm  * 2.5 cm = 2.5 cm^2 for the area of the triangle.

Adding those two together gets you a total area of 5.5 cm².

7 0
4 years ago
Read 2 more answers
Given that (y+z), (y+3) and (2y^2-1) are consecutive terms of an arithmetic progression. Find the possible values of y
Sphinxa [80]

Answer:

This problem actually says:

(y + 2), (y + 3) and (2*y^2 - 1) are consecutive terms of an arithmetic progression.

Now, the difference between two consecutive terms in an arithmetic progression is always the same, so we have:

(y + 3) - (y +2) = D

(2*y^2 - 1) - (y + 3) = D

From the first equation we have:

y + 3 - y - 2 = 1  = D

Now we can replace it in the other equation:

2*y^2 - 1 - y - 3 = 1

2*y^2 - y - 5 = 0

Now we need to solve that equation to find the possible values of y.

To solve a quadratic equation of the form:

a*x^2 + b*x + c = 0, we can use the Bhaskara's equation:

y = \frac{-b +- \sqrt{b^2 -4*a*c} }{2*a}

in this case, the solutions are:

y = \frac{1 +-\sqrt[]{(-1)^2 - 4*2*(-5)} }{2*2}  = \frac{1 +- \sqrt{61} }{4} = \frac{1+-6.4}{4}

Then the possible values of y are:

y = (1 + 6.4)/4 = 1.85

y = (1 - 6.4)/5 = -1.35

5 0
4 years ago
F(x) = (3.x4 + 1)2<br> Determine the total number of roots of each polynomial function
Black_prince [1.1K]

Answer:

6

Step-by-step explanation:

4 0
3 years ago
the lablel on a 1/2- pound bag of wildflower seeds states that it will cover an area of 375 square feet . based on this informat
dedylja [7]

Answer: so a 1 and 1/2 bag will cover 375

1=2/2

1 and 1/2=2/2 and 1/2=3/2

so 3/2 pound covers 375

2/2 pounds covers x

3/2pound=375

multiply both sides by 2 to get rid of the fraciton

3pound=750

divide both sides by 3

1pound=250 square feet so the answer is c. 250 square feet

Step-by-step explanation:

7 0
3 years ago
Plz answer fast!! i need help
netineya [11]

Answer: D) w = 9 feet

Work Shown:

L = \sqrt{w^2+h^2}\\\\L^2 = w^2+h^2\\\\L^2-h^2 = w^2\\\\w^2 = L^2-h^2\\\\w = \sqrt{L^2-h^2}\\\\w = \sqrt{15^2-12^2}\\\\w = \sqrt{225-144}\\\\w = \sqrt{81}\\\\w = 9\\\\

That points us to the final answer choice D.

6 0
3 years ago
Read 2 more answers
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