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Goryan [66]
3 years ago
8

Write the equation 4y - 10x = 10x + 8 in slope-intercept form.

Mathematics
2 answers:
gogolik [260]3 years ago
8 0

You would write it out as y = 5x +2

Nataly [62]3 years ago
7 0
Here you go, I hope I helped!

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PLS HELP GIVING (BRAINLY)
vitfil [10]

Answer:

i think D. 4x4x4 = 64 is answer

Step-by-step explanation:

4³ = 4×4×4 = 64

3 0
2 years ago
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Subtract the polynomials.
Mama L [17]

Answer:

B

Step-by-step explanation:

Given

(4x² - 3x - 4) - (3x² + 4x - 8) ← distribute by - 1

= 4x² - 3x - 4 - 3x² - 4x + 8 ← collect like terms

= x² - 7x + 4 → B

8 0
3 years ago
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Lines ℓ and m are intersected by transversal t. ℓ ∥ m. Lines l and m are horizontal with l above m and intersected by transveral
artcher [175]

Answer:

<5 = 105 degrees

Step-by-step explanation:

From the description given, since line l is parallel to m then <4 is alternate to <5 and two alternate angles are equal, if thst is the case

<4 = <5 (alternate angle)

Since <4 = 105 degrees, hence m<5 = 105 degrees

7 0
2 years ago
Show that (2xy3 + cos x)dx + (3x2 y2 − sin y)dy = 0 is exact, and find the solution. Find c if y(0) = π
Licemer1 [7]

We're looking for a solution of the form F(x,y)=C. By the chain rule, this solution should have total differential

\mathrm dF=\dfrac{\partial F}{\partial x}\,\mathrm dx+\dfrac{\partial F}{\partial y}\,\mathrm dy=0

and the equation is exact if the mixed second-order partial derivatives of Fare equal, i.e. \frac{\partial^2F}{\partial x\partial y}=\dfrac{\partial^2F}{\partial y\partial x}.

The given ODE is exact, since

\dfrac{\partial(2xy^3+\cos x)}{\partial y}=6xy^2

\dfrac{\partial(3x^2y^2-\sin y)}{\partial x}=6xy^2

Then

\dfrac{\partial F}{\partial x}=2xy^3+\cos x\implies F(x,y)=x^2y^3+\sin x+f(y)

\dfrac{\partial F}{\partial y}=3x^2y^2-\sin y=3x^2y^2+\dfrac{\mathrm df}{\mathrm dy}

\dfrac{\mathrm df}{\mathrm dy}=-\sin y\implies f(y)=\cos y+C

\implies x^2y^3+\sin x+\cos y=C

With y(0)=\pi, we get

\cos\pi=C\implies C=-1

\implies\boxed{x^2y^3+\sin x+\cos y=-1}

6 0
3 years ago
Show all work to factor x^4 − 17x^2 + 16 completely.
Dmitrij [34]

Answer:

x^{4}-17x^{2} +16 = (x -1)(x + 1)(x - 4)(x + 4)

Step-by-step explanation:

At first, let us find the first two factors of x^{4}-17x^{2} +16

∵ The sign of the last term is positive

∴ The middle signs of the two factors are the same

∵ The sign of the middle term is negative

∴ The middle signs of the two factors are negative

∵ x^{4} = x² × x² ⇒ first terms of the two factors

∵ 16 = -1 × -16 ⇒ second terms of the two factors

∵ x²(-1) + x²(-16) = -x² + -16x² = -17x² ⇒ the value of the middle term

∴ (x² - 1) and (x² - 16) are the factors of x^{4}-17x^{2} +16

Now let us factorize each factor

→ The factors of the binomial a² - b² (difference of two squares) are

   (a - b) and (a + b)

∵ x² - 1 is the difference of two squares

∴ Its factors are (x - 1) and (x + 1)

∵ x² - 16 is the difference of two squares

∴ Its factors are (x - 4) and (x + 4)

∵ (x -1), (x + 1), (x - 4), and (x + 4) are the factors of (x² - 1) and (x² - 16)

∵ (x² - 1) and (x² - 16) are the factors of x^{4}-17x^{2} +16

∴ (x -1), (x + 1), (x - 4), and (x + 4) are the factors of x^{4}-17x^{2} +16

∴  x^{4}-17x^{2} +16 = (x -1)(x + 1)(x - 4)(x + 4)

8 0
2 years ago
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