-6 / 2 = -3 so
x^2 - 6x + 8 is
(x - 3)^2 -9 + 8
= (x - 3)^2 - 1
the vertex is at (3,-1)
Answer:
8 - (3 x 2) - (1 + 1) = 0
or
8 - 3 x 2 - (1 + 1) = 0
Remember PEMDAS.
If I put parenthesis around 3 x 2, I get 6.
But 8 - 6 = 2
How can we make 2 - 1 + 1 = 0?
If we look at PEMDAS, we know (2 - 1) + 1 = 2, but the answer needs to be 0.
So now try 2 - (1 + 1) and that gives me 0.
And it says parentheses...but you can also do 8 - 3 x 2 - (1 + 1) = 0.
Answer:
(0, -3)
Step-by-step explanation:
y = 3x - 3
y = x - 3
In the solution to the system of equations, y is the same number for both of those functions. So 3x - 3 = x - 3.
Then solve for x:
3x - 3 = x - 3
Add 3 to both sides
3x = x
Subtract x from both sides
2x = 0
Divide both sides by 2
x = 0
Now that you have x, substitute it in one of the equations:
y = 3x - 3
y = 3(0) - 3
y = -3
x is 0 and y is -3, so the solution to the equation is (0, -3)
2x2x1= 4 possible ways
GBP & BPP & BB
GBP & RPP & BB
YBP & BPP & BB
YBP & RPP & BB
GBP is green backpack, YBP is yellow backpack, BPP is blue pencil pouch, RPP is red pencil point, BB is black binder.
radians.