Considering the reaction of hydrogen and oxygen to produce water. If 24.6 g of water is produced and 2.9 g of hydrogen is used, the amount of oxygen needed is 21.87 grams
The best way to solve this question is to write out the reaction between hydrogen and oxygen that resulted in the formation of water.
So, we have:
From the above reaction;
2 moles of hydrogen gas reacted with 1 mole of oxygen to produce 2 moles of water.
If;
- 1 mole of O₂ = 32 grams of O₂
- 2 mole of H₂O = 2 × 18 grams of H₂O
- 2 mole of H₂O = 36 grams of H₂O
We can deduce that since 1 mole of O₂ produced 2 moles of H₂O;
Thus, 32 grams of O₂ is needed to produce 36 grams of H₂O.
∴
To produce, 24.6 grams of H₂O, we have:
= 21.87 grams of oxygen.
Therefore, we can conclude that the amount of oxygen needed is 21.87 grams.
Learn more about chemical reactions here:
brainly.com/question/1689737?referrer=searchResults
Mass of the shells will remain constant.
Explanation:
Sedimentary rocks are formed by the rocks that have been weathered. The microscopic shells, small pieces of rocks and mineral particles get deposited on this weathered sedimentary rocks.
The texture or chemical properties of the microscopic shell get changed. but the amount of microscopic shell deposited to make sedimentary rocks remains the same.
Chalk and coral reefs are the example of sedimentary rocks made up with microscopic shells.
The skeletal part of the shells takes part in rock formation whose mass remains unchanged although physical and chemical properties go changes.
Answer:
the amount of atoms and particle I think is in here is 17 that oxygen and water can hold with the amount of barium hydrogen.
Answer:
ur answer, hope it helps you...
