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Snezhnost [94]
3 years ago
7

Scientists are trying to produce a chemical reaction using two substances. After observing the substances, they realize that the

re is not
enough energy to make the reaction they had hoped for. In this case, what would they need to add to the mixture to produce a quicker
reaction?
O A base
O An acid
O UV light
O A catalyst
Chemistry
2 answers:
777dan777 [17]3 years ago
5 0

Answer:

A catalyst

Explanation:

Catalysts make reaction faster and speed up the reaction time.

MArishka [77]3 years ago
3 0

Answer: NOT a base

Explanation: i just took the exam and got this one wrong but i donno the correct answer between the last 3 good luck bb

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Who made the first periodic table
ale4655 [162]
The other dude is rude wrong

The correct answer is Dmitri Mendeleev
8 0
3 years ago
2KClO3 —> 2KCl2+ 3O2
garik1379 [7]

Answer:

False. The balanced equation should be

2KClO3-->2KCl + 3O2

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3 0
3 years ago
The successive ionization energies of a certain element are I1 = 589.5 kJ/mol, I2 =1145 kJ/mol, I3= 4900 kJ/mol, I4 = 6500 kJ/mo
Gnom [1K]

Answer:

As

Explanation:

For any element to exhibit the pattern of ionization energy shown in the question, it must possess five electrons in its outermost shell. These five electrons are not lost at once. They are lost progressively until the valence shell becomes empty. The ionization energy increases steadily as more electrons are lost from the valence shell.

The only pentavalent element among the options in arsenic, hence the answer.

7 0
4 years ago
Read 2 more answers
3. If x electrons are needed to displace 108 g silver from a solution which contains Ag ions,
ss7ja [257]

Answer:

Choice A. x electrons would be required for displacing 9\; \rm g of aluminum from a solution of \rm Al^{3+} ions.

Assumption: by "\rm Ag ions" the question meant \rm Ag^{+} with a charge of +1 on each ion.

Explanation:

The question states that the relative atomic mass of \rm Ag is 108. In other words, each mole of

Therefore, that 108\; \rm g\! of silver that were formed would contain 1\; \rm mol of silver atoms.

Metallic silver would precipitate out of this \rm Ag^{+} solution only after these ions are turned into \rm Ag atoms.

One \rm Ag^{+} ion carries one unit of positive electrical charge. On the other hand, each  e^{-} carries one unit of negative electrical charge.

Therefore, each \rm Ag^{+}\! ion will need to gain one electron to form a neutral \rm Ag atom.

{\rm Ag^{+}}\; (aq) + e^{-} \to {\rm Ag}\; (s).

At least  1\; \rm mol of electrons would be required to turn 1\; \rm mol\! of \rm Ag^{+} ions into that 1\; \rm mol\!\! of silver atoms (which have a mass of 108\; \rm g\!.)

Hence, x = 1\; \rm mol.

Unlike \rm Ag^{+} ions, each aluminum ion \rm Al^{3+} carries three units of positive electrical charge. That is three times the amount of charge on one \rm Ag^{+}\! ion. Therefore, three electrons will be required to turn one \rm Al^{3+}\! ion to an \rm Al atom.

{\rm Al^{3+}}\; (aq) + 3\, e^{-} \to {\rm Al}\; (s)

The question states that the relative atomic mass of \rm Al is 27. Therefore, each mole of \rm Al\! atoms would have a mass 27\; \rm g. There would be \displaystyle \frac{9\; \rm g}{27\; \rm g \cdot mol^{-1}} = \frac{1}{3} \; \rm mol of atoms in that 9\; \rm g of \rm Al\!\!.

It takes 3\; \rm mol of electrons to turn one mole of \rm Al^{3+} ions to one mole of \rm Al atoms. Hence, \displaystyle \frac{1}{3}\times 3\; \rm mol = 1\; \rm mol of electrons would be required to produce that \displaystyle \frac{1}{3}\; \rm mol of \rm Al\! atoms (which has a mass of 9\; \rm g) from \rm Al^{3+}\! ions.

That corresponds to the first choice, x electrons.

7 0
3 years ago
An atom has 30 protons, 21 neutrons, and 19 electrons. Is this an ion? If so, what type of ion is this?
marissa [1.9K]

Answer:

An atomic number

Explanation:

If a neutral atom has 30 protons and 34 neutrons, the number of electrons in the atom is: A) 94. B) 34. 64. ... 17) What is the symbol for the ion with 19 protons and 18 electrons? A) F+. B) K+ ... 21) Identify the metalloid in the following list. Hope this helps you! Ask me anything if you have any quistions!

7 0
4 years ago
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