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Bond [772]
3 years ago
6

In ΔLMN, \overline{LN} LN is extended through point N to point O, m∠NLM = (x+1)^{\circ}(x+1) ∘ , m∠LMN = (x+15)^{\circ}(x+15) ∘

, and m∠MNO = (4x+6)^{\circ}(4x+6) ∘ . Find m∠MNO.
Mathematics
1 answer:
mixer [17]3 years ago
3 0

Answer:

26 degree

Step-by-step explanation:

We are given that  in triangle

\angle NLM=(x+1)^{\circ}

\angke LMN=(x+15)^{\circ}

\angle MNO=(4x+6)^{\circ}

\angle MNO+\angle MNL=180^{\circ}

By using linear pair angles property

\angle MNL=180-\angle MNO=180-(4x+6)

\angle MNL+\angle NLM+\angle LMN=180^{\circ}

By using triangle angles sum property

180-(4x+6)+x+15+x+1=180

2x+16=180-180+4x+6

16-6=4x-2x=2x

2x=10

x=\frac{10}{2}=5

Substitute the value

\angle MNO=4(5)+6=20+6=26^{\circ}

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Answer:

a)There is a 4.88% probability that none is concerned that employers are monitoring phone calls.

b)There is a 7.89% probability that all are concerned that employers are monitoring phone calls.

c)There is a 37.23% probability that exactly two are concerned that employers are monitoring phone calls.

Step-by-step explanation:

The binomial probability is the probability of exactly x successes on n repeated trials in an experiment which has two possible outcomes (commonly called a binomial experiment).

It is given by the following formula:

P = C_{n,x}.p^{n}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of a success.

In this problem, a success is being concerned that employers are monitoring phone calls.

53% of adults are concerned that employers are monitoring phone calls, so p = 0.53

(a) Out of four adults, none is concerned that employers are monitoring phone calls.

Four adults, so n = 4.

Is the probability of 0 successes, so x = 0.

P = C_{n,x}.p^{n}.(1-p)^{n-x}

P = C_{4,0}.(0.53)^{0}.(0.47)^{4}

P = 0.0488

There is a 4.88% probability that none is concerned that employers are monitoring phone calls.

(b) Out of four adults, all are concerned that employers are monitoring phone calls.

Four adults, so n = 4.

Is the probability of 4 successes, so x = 4.

P = C_{n,x}.p^{n}.(1-p)^{n-x}

P = C_{4,0}.(0.53)^{4}.(0.47)^{0}

P = 0.0789

There is a 7.89% probability that all are concerned that employers are monitoring phone calls.

(c) Out of four adults, exactly two are concerned that employers are monitoring phone calls.

Four adults, so n = 4.

Is the probability of 4 successes, so x = 2.

P = C_{n,x}.p^{n}.(1-p)^{n-x}

P = C_{4,2}.(0.53)^{2}.(0.47)^{2}

P = 0.3723

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3 0
3 years ago
Please help it would be very appreciated!!
Leto [7]

Answer:

answer is 24.56cm

perimeter of half/semi circle =  \pi r + 2r

<em>one semi circle semi circles perimeter:  </em>\pi<em>*2+2*2 =10.283cm, </em>

<em>for two semi circles= 2*10.283 =20.566cm</em>

without the line below for two semi circle: 20.566-4-4=12.566 cm

both da side of rectangle is 6cm+6cm=12cm

now add the 12.566+12=24.56cm

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