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Bond [772]
3 years ago
6

In ΔLMN, \overline{LN} LN is extended through point N to point O, m∠NLM = (x+1)^{\circ}(x+1) ∘ , m∠LMN = (x+15)^{\circ}(x+15) ∘

, and m∠MNO = (4x+6)^{\circ}(4x+6) ∘ . Find m∠MNO.
Mathematics
1 answer:
mixer [17]3 years ago
3 0

Answer:

26 degree

Step-by-step explanation:

We are given that  in triangle

\angle NLM=(x+1)^{\circ}

\angke LMN=(x+15)^{\circ}

\angle MNO=(4x+6)^{\circ}

\angle MNO+\angle MNL=180^{\circ}

By using linear pair angles property

\angle MNL=180-\angle MNO=180-(4x+6)

\angle MNL+\angle NLM+\angle LMN=180^{\circ}

By using triangle angles sum property

180-(4x+6)+x+15+x+1=180

2x+16=180-180+4x+6

16-6=4x-2x=2x

2x=10

x=\frac{10}{2}=5

Substitute the value

\angle MNO=4(5)+6=20+6=26^{\circ}

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a=49.5 -1.28*15=30.3

So the value of height that separates the bottom 10% of data from the top 90% is 30.3.  

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Step-by-step explanation:

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Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

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Where \mu=49.5 and \sigma=15

We are interested in the bottom 10% of the data.

For this part we want to find a value a, such that we satisfy this condition:

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P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

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So the value of height that separates the bottom 10% of data from the top 90% is 30.3.  

If the score is lower than 30.3 we consider this score as risk averse

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