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Blababa [14]
3 years ago
6

60 over 100 as a decimal

Mathematics
1 answer:
pshichka [43]3 years ago
8 0

Answer:

0.6

Explanation: 60 over 100 would be 60/100, so when converting this into a decimal, the 60 would be in the hundreths place. Therefore, the decimal would be 0.6.

Hope this Helps!

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What two numbers multiply to -20 then add to -8?
VARVARA [1.3K]

Answer:

-10 and 2

Step-by-step explanation:

1.  Think about what numbers multiply to -20:  -10 and 2, 10 and -2, -20 and 1, 20 and -1, 4 and -5, -4 and 5

2.  Then, think about which of the above adds to -8.  This leaves you with -10 and 2

7 0
3 years ago
Read 2 more answers
If f(x) = 2(3x) + 1, what is the value of f(2)?
Over [174]
F(2)=2(3*2)+1
f(2)=2(6)+1
=13
answer is 13
4 0
3 years ago
What is 15ft by 18ft times 2in depth converted into yards
NeTakaya

Answer:

5 yd³

Step-by-step explanation:

2 in = 1/6 ft

15 ft  ×  18 ft  ×  1/6 ft = 45 ft³

1 ft³ = 9 yd³

45 ft³/9 = 5 yd³

4 0
3 years ago
Given that the quadratic equation has equal roots (k^2-1)x^2-2kx-3k-1=0
Alik [6]

Answer:

(See explanation for further details)

Step-by-step explanation:

The real expression is:

(k^{2}-1)\cdot x{{2} - 2\cdot k \cdot x - 3\cdot k + 1 = 0

The general equation for the second-order polynomial is:

x = \frac{2\cdot k \pm \sqrt{4\cdot k^{2}-4\cdot (k^{2}-1)\cdot (-3\cdot k + 1)}}{k^{2}-1}

This condition must be observed for the case of a quadratic equation with equal roots:

4\cdot k^{2} - 4\cdot (k^{2}-1)\cdot (-3\cdot k + 1) = 0

k^{2} + (k^{2}-1)\cdot (3\cdot k + 1) = 0

k^{2} + 3\cdot k^{3} - 3\cdot k - k^{2}-1 = 0

3\cdot k^{3} - 3\cdot k - 1 = 0

7 0
3 years ago
<br> NEED HELP ASAP PLEASE HELP ME!!!
jeyben [28]

Answer:

The second option

Step-by-step explanation:

The answer is negative (The blue line is below the x axis)

for all x values between -2 and -6  is a true statement

The first option is incorrect because the function is negative between -4 and -2.

The third option is incorrect because the function is negative between -3 and -2.

The forth option is incorrect because the function is positive for x < -6.

8 0
3 years ago
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