Ask question

Ask question

All categories

3 years ago

10

Daniela scored 101101101 points in 555 basketball games. Casey scored 154154154 points in 888 games. Hope scored 227227227 point

s in 121212 games.

2 answers:

8_murik_8 [283]3 years ago

5 0

What’s the question————-??????!!!!!?????

ch4aika [34]3 years ago

3 0

i am completely confused how is this even physically possible what the heck

You might be interested in

Need help on 25. Please show your work

Alexxx [7]

Base B (aka p) is equivalent to 18
p=18

3 0

3 years ago

Can Anyone Help me with this I believe I got the first one correct If not correct me please

olga_2 [115]

Answer:

the second one I think

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Factor this completely thank you

jeka94

4(2x raise to power 2-4-7x)

3 0

2 years ago

In the diagram, BC is a radius of C. Determine whether AB is tangent to C. Explain your reasoning.

Whitepunk [10]

Answer:

No, AB is not tangent to C.

If it were tangent, it would form a right angle with the radius, and we could use Pythagorean's Theorem.

3²+6²=7²

9+36=49

45=49 Since this is false, it's not a right angle, and AB is not tangent.

Step-by-step explanation:

No, AB is not tangent to C.

If it were tangent, it would form a right angle with the radius, and we could use Pythagorean's Theorem.

3²+6²=7²

9+36=49

45=49 Since this is false, it's not a right angle, and AB is not tangent.

6 0

2 years ago

It costs more to produce defective items - since they must be scrapped or reworked - than it does to produce non-defective items

ale4655 [162]

Answer: a) 1082, b) wider.

Step-by-step explanation:

Since we have given that

Margin of error = 0.1 millimeter = E

Standard deviation = 2 mm = σ

Critical value would be

$z_{\frac{\alpha}{2}}=z_{0.05}=1.645$

a) Sample size would be

$n=(\dfrac{z_{\frac{\alpha }{2}}\times \sigma}{E})^2\\\\n=(\dfrac{1.645\times 2}{1})^2\\\\n=1082.41\\\\n=1082$

b) Sample size, n = 100

So, the margin of error would be

$E=z_{\frac{\alpha }{2}}\times \dfrac{\sigma}{\sqrt{n}}\\\\E=1.645\times \dfrac{2}{\sqrt{100}}\\\\E=1.645\times \dfrac{2}{10}\\\\E=0.329$

Since the margin of error in b part is more than a part, as we know that the higher the margin of error, the wider the confidence interval.

So, it would have wider confidence interval.

Hence, a) 1082, b) wider.

4 0

3 years ago