Y^4-4y^3+7y^2-6y-2y^3+8y^2-14y+12=
y^4-6y^3+15y^2-20y+12
or
y^3-4y^2+7y-6=y^3-4y^2+4y+3y-6=
y(y^2-4y+4)+3(y-2)=
y(y-2)^2+3(y-2)=(y-2)[y(y-2)+3]=(y-2)(y^2-2y+3)
(y^3-4y^2+7y-6)(y-2)=(y-2)^2(y^2-2y+3)
Answer:
(1)-
b1 =~3.4
bo= ~ 82.8
(2)- ý=[82.8]+[3.4] x
(3)- The change in annual sales ($1000) for every year of experience is= 3.4
(4)-r^2=~ 0.847
Estimated annual sales= $110514
Step-by-step explanation:
(1)- b1 = 3.4606
=~3.4
bo = 82.8296
= ~ 82.8
(2)-
ý=[82.8]+[3.4] x
(3)-The change in annual sales ($1000) for every year of experience is= 3.4
(4)- r^2 = 0.84776
=~ 0.847
Percentage of the variation in annual sales can be explained by the years of experience
of the salesperson 84.7%.
Estimated annual sales
= 82.8296 + 3.4606 × 8 ($ 1000).
= 110.5144 ( $1000)
= $ 110514:4
= $110514
Answer:
9cm^2
Step-by-step explanation:
Answer:
<h2><em>
2x-4</em></h2>
Step-by-step explanation:
Area of a rectangle = Length * Width
Given parameters
Area A = 8x2 – 10x – 12
Length of the rectangle = 4x+3
Required
Width of the rectangle.
Substituting the given parameters into the formula
8x2 – 10x – 12 = (4x+3)*width
width = 8x2 – 10x – 12
/4x+3
S
Factorizing the numerator
8x² – 10x – 12
= 2(4x²-5x-6)
= 2(4x²-8x+3x-6)
= 2(4x(x-2)+3(x-2))
= 2(4x+3)(x-2)
Width = 2(4x+3)(x-2)/4x+3
Width = 2(x-2)
Width = 2x-4
<em>Hence the width of the rectangle is 2x-4</em>
First box is EF.
Second box is segment congruence postulate.
Third box is segment additon postulate.
Fourth box is DF. For this one the last sentence basically gives you the answer.
Just so you know for the fourth I guessed on if it's DF lined or DF unlined. I made my educated guess on the fact that the last line doesn't have a line. I hope this helps, and please tell me if I got something wrong, or my explanation wasn't sufficent enough for you.
