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Stells [14]
3 years ago
15

PLS HELP DUE SOON!! (retest) will give brainliest <3

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
8 0

Answer:

B and D

Step-by-step explanation:

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The mean of your question would be -2.5
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Samantha drives 2,100 miles each week how many miles does she drive in 4 weeks​
adelina 88 [10]

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Find the missing length of the following trapezoid
Schach [20]

Answer:

1) The length of DC is 20.

2) The length of PS is 17.

Step-by-step explanation:

1) If DR = RE and CS = SB, then we can use the following proportionality ratio:

\frac{DE}{DR} = \frac{32 - x}{26 - x} (1)

Where x is the length of segment \overline{CD}.

If DE = 2\cdot DR, then the value of x is:

2 = \frac{32-x}{26-x}

52 - 2\cdot x = 32 - x

20 = x

The length of DC is 20.

2) If QV = VP and RW = WS, then we can use the following proportionality ratio:

\frac{QP}{QV} =  \frac{x-7}{12-7} (2)

Where x is the length of segment \overline{PS}.

If QP = 2\cdot QV, then the value of x is:

2 = \frac{x-7}{5}

10 = x-7

x = 17

The length of PS is 17.

4 0
3 years ago
Greg pulls two coins out of his pocket randomly without replacement. If his pocket contains one nickel, one dime, and one quarte
Verdich [7]
I believe the probability would be 2/3
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3 years ago
Consider the following probability distribution function of the random variable X which represents the number of people in a gro
Troyanec [42]

Answer:

(a) 3.55

(b) 3.45 and 1.86

(c) 0.25

(d) 0.016

Step-by-step explanation:

The random variable <em>X</em> denotes the number of people in a group (party) at a restaurant.

(a)

The formula to compute the mean is:

\mu=\sum {x\cdot P(X=x)}

Consider the Excel sheet attached.

The mean is, 3.55.

(b)

The formula to compute the variance is:

\sigma^{2}=[\sum {x^{2}\cdot P(X=x)}]-(\mu)^{2}

Consider the Excel sheet attached.

Compute the variance as follows:

\sigma^{2}=[\sum {x^{2}\cdot P(X=x)}]-(\mu)^{2}\\\\=16.05-(3.55)^{2}\\\\=3.4475\\\\\approx 3.45

The variance is, 3.45.

Compute the standard deviation as follows:

\sigma=\sqrt{\sigma^{2}}\\\\=\sqrt{3.45}\\\\=1.85742\\\\\approx 1.86

The standard deviation is, 1.86.

(c)

Compute the probability that the next party will be over 4 people as follows:

P(X>4)=P(X=5)+P(X=6)+P(X=7)+P(X=8)\\\\=0.10+0.05+0.05+0.05\\\\=0.25

Thus, the probability that the next party will be over 4 people is 0.25.

(d)

Compute the probability that the next three parties will each be over 4 people as follows:

It is provided that the three parties are independent.

P (Next 3 parties will be each over 4) = [P (X > 4)]³

                                                           =(0.25)^{3}\\=0.015625\\\approx 0.016

Thus, the probability that the next three parties will each be over 4 people is 0.016.

3 0
2 years ago
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