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Anni [7]
3 years ago
5

If 400g; 1kgfind the ratio in Simplest form.​

Mathematics
1 answer:
Aloiza [94]3 years ago
6 0

Answer:

ASK UR STEP-SEX BUDY

Step-by-step explanation:

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Write an equation of the line that passes through (2,7) and is parallel to the line shown ( please help !! )
Anna007 [38]

Answer:

y=2x+3

Step-by-step explanation:

We will first need to determine the slope of the line shown.

We know that it passes through the two points (-2, -2) and (1, 4).

Thus, we can use the slope formula to find the slope between the two points:

\displaystyle m=\frac{y_2-y_1}{x_2-x_1}

Let (-2, -2) be (x₁, y₁) and let (1, 4) be (x₂, y₂). Substitute:

\displaystyle m=\frac{4-(-2)}{1-(-2)}=\frac{6}{3}=2

Hence, the slope of the original line was 2.

Since we want the new line to be parallel, the slope of the new line must also be 2.

We know that the slope is 2 and it passes through the point (2, 7).

So, we can use the point-slope form:

y-y_1=m(x-x_1)

We will substitute 2 for m. We will also let (2, 7) be (x₁, y₁). Substitute:

y-7=2(x-2)

Solve for y. Distribute the right:

y-7=2x-4

Add 7 to both sides. Hence, our equation is:

y=2x+3

6 0
2 years ago
40 is the sum of 15 and Craig's savings.<br> Use the variable c to represent Craig's savings.
andrew-mc [135]
40=15+c

Hope it helps
8 0
3 years ago
Read 2 more answers
What is equivalent to
Alenkinab [10]

Answer:

1 : equal in force, amount, or value also : equal in area or volume but not superposable a square equivalent to a triangle. 2a : like in signification or import. b : having logical equivalence equivalent statements. 3 : corresponding or virtually identical especially in effect or function.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Convert 76,000 ml into L. Please show your work.
ser-zykov [4K]
Ok so there are 1,000 ml in every liter so
76000 ml= L which is a thousand ml
76000/1000
=76 L


5 0
3 years ago
T F IfA and B are similar matrices, then AT=BT
muminat

Answer:

Step-by-step explanation:

We know that for two similar matrices A and B exists an invertible matrix P for which

[tex]B = P^{-1} AP[/tex]

∴ B^{T} = (P^{-1})^{T} A^{T} P^{T} \\

Also P^{-1}P = I\\

and (P^{-1})^{T} = (P^{T})^{-1}

∴(P^{-1})^{T}P^{T} = I

so, B^{T} = (P^{-1})^{T} A^{T} P^{T} = (P^{T})^{-1}A^{T} P^{T}\\B^{T} = A^{T} I\\B^{T} = A^{T}

7 0
3 years ago
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