To solve this problem you must apply the proccedure shown below:

1. You have the following expressions shown in the problem above:

(8m^2-6/n+3) + (9m^2-4/n+3)

2. As you can see, they have equal denominators, then you have:

(8m^2-6+ 9m^2-4)/(n+3)

3. Therefore, when you sum, you have the following result:

(17m²-10)/(n+3)

The answer is: (17m²-10)/(n+3)

4 0

3 years ago

The following data represent the pH of rain for a random sample of 12 rain dates. a normal probability plot suggest the data cou

babunello [35]

Answer:

Step-by-step explanation:

a) Estimate for population mean = Sum/n = $\frac{59.1}{12} =4.925$

b) Variance = 0.099208

Std dev = 0.314974

Std error = 0.0950

For 95% margin of error = 1.96*Std error

=0.1861

Confidence interval = $(4.925-0.1861, 4.925+0.1861)\\=(4.7389, 5.1111)$

Interpretation of confidence interval:

A) if repeated samoles are taken, 95% of them will have a sample pH of rain water between [ ] & [ ].

For 99% CI, z value = 2.59

Conf interval = (4.6790, 5.1710)

C)if repeated samoles are taken, 99% of them will have a sample pH of rain water between [ ] & [ ].

As the level of confidence increases l, the width of the interval[ increases] this makes sense since the [ margin of error] [increases]

3 0

3 years ago