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vovangra [49]
3 years ago
12

8m²n³-24m²n²+4m³n how do I factor out the GCF

Mathematics
1 answer:
mariarad [96]3 years ago
6 0

Answer:

8 {m}^{2}  {n}^{3}  - 24 {m}^{2} {n}^{2}   + 4 {m}^{3}n = 4 {m}^{2} n(2 {n}^{2}  - 6n + m)

Step-by-step explanation:

The given expresion is

8 {m}^{2}  {n}^{3}  - 24 {m}^{2} {n}^{2}   + 4 {m}^{3}n

Observe that 4 is common to 8,-24, and 4

Observe also that, m²n is common to all the terms.

Hence the GCF is:4m²n

We factor the GCF to get;

8 {m}^{2}  {n}^{3}  - 24 {m}^{2} {n}^{2}   + 4 {m}^{3}n = 4 {m}^{2} n(2 {n}^{2}  - 6n + m)

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X^2 - 12x + 19 in the form of (x + a)^2 + b ???
kow [346]

Answer:

( x-6)^2 -17

Step-by-step explanation:

X^2 - 12x + 19

we need it in given below form

(x + a)^2 + b

we know that

(x + a)^2 = x^2 + 2ax + a^2\\

lets convert that in same form

X^2 - 12x + 19 = x^2 + 2(-6)x + 19

comparing x^2 + 2(-6)x to x^2 + 2ax

we have a -6

now

(x-6)^2 = x^2 + 2(-6)x + 36

36 is missing in the x^2 + 2(-6)x + 19 hence to get that

we add and subtract 36 in the above equation

so we have

x^2 + 2(-6)x + 19 + 36 -36

rearranging  it \

(x^2 + 2(-6)x  + 36) -36 + 19    (x^2 + 2(-6)x  + 36 =( x-6)^2)

=>( x-6)^2 -17

comparing the above equation to

(x + a)^2 + b

we have a = -6

b = -17

( x-6)^2 -17

7 0
3 years ago
Which expression gives the distance between the points (4,6)and (7,-3)
amid [387]
The distance between any two points is:

d^2=(x2-x1)^2+(y2-y1)^2 so in this case:

d^2=(7-4)^2+(-3-6)^2

d^2=3^2+9^2

d^2=90

d=√90

d=3√10 units 

d≈9.49 units (to nearest hundredth of a unit)
3 0
3 years ago
How’s everyone been?
topjm [15]

I don't know I can't speak for the 6 billion other werid people on the planet.

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What is the function rule represented by the following table?
Romashka-Z-Leto [24]

Answer:

y=-4x+3

Step-by-step explanation:

as x=0

put in y= -4x+3

y= -4(0)+3

y=3

now put x=1 in y= -4x+3

y= -4(1)+3

y= -1

now put x=2 in y= -4x+3

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3 years ago
Which expression is equivalent to 113−−−√5?
Anna35 [415]

Answer:

_

113 -✓5

Step-by-step explanation:

_

113-(-(-✓5))

_

=113-✓5 (decimal:110.763932)

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