So first factor it
1008=2*2*2*2*3*3*7
group them in similar pairs
1008=(2*2)(2*2)(3*3)*7
now remember we can do
so
=
2*2*3*
=
12√7
the answer is B
Answer:
A
Step-by-step explanation:
The intervals are given as follows:
- In range notation: [-282, 20,320].
- In set-builder notation: {x|x ∈ ℝ, -282 <= x <= 20,320}
<h3>What is the range of elements notation for interval?</h3>
The range of elements notation for interval is given by:
[a,b].
In which:
In this problem these values are given by:
a = -282, b = 20,320.
Hence the interval in range notation is given by:
[-282, 20,320].
<h3>How to write the interval in set-builder notation?</h3>
The same interval can be written as follows, using set-builder notation?
{x|x ∈ ℝ, a <= x <= b}
Hence, for the situation described in this problem, the set-builder notation for the values is:
{x|x ∈ ℝ, -282 <= x <= 20,320}
More can be learned about notation of intervals at brainly.com/question/27896097
#SPJ1
Perfect squares are n² where n is a whole number
whole numbers are like 0,1,2,3,4,5,6, etc
no decimal or fractions
we can do that be looking at the perfect squares we know
2²=4
3²=9
4²=16
5²=25
6²=36
7²=49
8²=64
etc
so we see 47 is between 6² and 7²
therefor, for n²=47, n is between 6 and 7 and is therfore not a whole number
that makes 47 not a perfect square
