Rearrange
to give
Let
be a variable 'p' and so we can write
as
Rewrite the equation in terms of 'p'
where
using the quadratic formula
and subsitute the value of
There are two value of p; 125 and -27
Now we find the value of x
Earlier we substitute
for
and
for
When
,
![x= \sqrt[3]{125}=5](https://tex.z-dn.net/?f=x%3D%20%5Csqrt%5B3%5D%7B125%7D%3D5%20)
When
![p = -27, x= \sqrt[3]{-27}=-3](https://tex.z-dn.net/?f=p%20%3D%20-27%2C%20x%3D%20%5Csqrt%5B3%5D%7B-27%7D%3D-3%20)
So the final answer is the two values of x;
x = 5 OR x = -3
<span>A) Goats that weigh exactly 50 or 60 pounds fall into two classes. would be the right answer</span>
Answer:
1) 4:7
2) 3:1
3) $0.50 per ounce
4) 7.5 degrees per hour
5) 61 mils per hour
6) 30 pounds per box
7) $1.89 per notebook
8)
a. 3 centerpieces for party per hour
b. 14 hours
Given:
8:03 = 188 empty seats
8:10 = 160 empty seat
188 - 160 = 28 empty seats
8:10 - 8:03 = 0:07 minutes
28 / 7 minutes = 4 empty seats per minute
8:00 - 8:03 = 3 minutes
3 minutes * 4 seats per minute = 12 seats
188 + 12 = 200 empty seats at 8:00
8:15 - 8:10 = 0:05 minutes
5 minutes * 4 seats per minute = 20 empty seats
160 - 20 = 140 empty seats at 8:15
200 - 120 = 80 empty seats
80 empty seats / 4 empty seats per minute = 20 minutes
120 empty seats at 8:20.
8:00 = 200 empty seats
200 / 4 = 50 minutes
8:00 + 0:50 = 8:50 is the time when there are no empty seats left.
I put a step by step on the picture, I thought it would be easier than words. Hope this helps!
