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3 years ago

Square root 8 to the nearest hundredth

Mathematics

1 answer:

yawa3891 [41]3 years ago

5 0

Answer:

2.83

Step-by-step explanation:

just round to the nearest hundredth

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Find the measure of the angle formed between the base of the cone and a line segment that represents the slant height

wel

Since there are no figures given, I will give an example.

You are given a silo that is shaped as a closed cylinder with a conical end. The diameter of the silo is 4 ft, the length of the cylindrical part is 6 ft, and the entire length of the silo is 10.5 ft. Suppose that you are asked to find the total volume of grains that can be stored in the silo.

Given:

Cylinder part

D = 4 ft

H = 6 ft

Cone part

H = 10.5 – 6 = 4.5ft

D = 4ft

Required:

Volume of silo

Solution:
V of cylinder = πr²H

V of cylinder = π(4/2)²(6)

V of cylinder = 75.4 ft³

V of cone = πr²H/3

V of cone = π(4/2)²(4.5/3)

V of cone = 18.85 ft³

Total volume = 94.25 ft³

6 0

3 years ago

Three forces act on a hook. Determine the magnitude of the resultant of the force.

Novay_Z [31]

Use Hooke's law... (just kidding)

Break down each force vector into horizontal and vertical components.

$\vec F_1=(1000\,\mathrm N)(\cos30^\circ\,\vec x+\sin30^\circ\,\vec y)\approx(866.025\,\mathrm N)\,\vec x+(500\,\mathrm N)\,\vec y$

$\vec F_2=(1500\,\mathrm N)(\cos160^\circ\,\vec x+\sin160^\circ\,\vec y)\approx(-1409.54\,\mathrm N)\,\vec x+(513.03\,\mathrm N)\,\vec y$

$\vec F_3=(750\,\mathrm N)(\cos195^\circ\,\vec x+\sin195^\circ\,\vec y)\approx(-724.444\,\mathrm N)\,\vec x+(-194.114\,\mathrm N)\,\vec y$

The resultant force is the sum of these vectors,

$\vec F=\displaystyle\sum_{i=1}^3\vec F_i\approx(-1267.96\,\mathrm N)\,\vec x+(818.916\,\mathrm N)\,\vec y$

and has magnitude

$|\vec F|\approx\sqrt{(-1267.96\,\mathrm N)^2+(818.916\,\mathrm N)^2}\approx1509.42\,\mathrm N$

The closest answer is D.

5 0

3 years ago

Solve for x. Each figure is a trapezoid. # 18 has a midsegment. 13)

Vanyuwa [196]

Question 13

${12x+2}=\frac{18+34}{2}\\\\12x+2=26\\\\12x=24\\\\x=\boxed{2}$

Question 14

Base angles of an isosceles trapezoid are congruent, so:

$73x+1=74\\73x=73\\x=\boxed{1}$

3 0

2 years ago

For each of the equations below, solve for y in terms of x. ! a. 2x – 3y = 12

ira [324]

Answer:

$\large\boxed{y=\dfrac{2}{3}x-4}$

Step-by-step explanation:

$2x-3y=12\qquad\text{subtract}\ 2x\ \text{from both sides}\\\\2x-2x-3y=12-2x\\\\-3y=12-2x\qquad\text{divide both sides by (-3)}\\\\\dfrac{-3y}{-3}=\dfrac{12}{-3}+\dfrac{-2x}{-3}\\\\y=-4+\dfrac{2}{3}x$

7 0

3 years ago

Urgent!!!!!!!!!!!!!!!!!!

MAVERICK [17]

24 right box VEDR - 6(4)
9 Left triangle VMR - 0.5 (6)(3)
24 + 9 = 33

6 0

2 years ago