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baherus [9]
3 years ago
11

The answer to all of these problems

Mathematics
1 answer:
-BARSIC- [3]3 years ago
4 0
1) area of a cicular pool
area of a circle=πr^2   d=2.5 then r=2.5/2
A=3.14 *(2.5/2)^2
A=4.906m^2 A=4.9m^2

2) arae of a coin 
<span>(if i read it right d=15mm?)
</span>A=πr^2   d=15 then r=15/2
A=3.14*(15/2)^2 =176.6mm^2


Rest all are same problems u try to solve it
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Use the Fundamental Theorem of Calculus to find the area of the region between the graph of the function x5 + 8x4 + 2x2 + 5x + 1
belka [17]

Answer:

The area of the region between the graph of the given function and the x-axis = 25,351 units²

Step-by-step explanation:

Given  x⁵ + 8 x⁴ + 2 x² + 5 x + 15

If 'f' is a continuous on [a ,b] then the function

            F(x) = \int\limits^a_b {f(x)} \, dx

By using integration formula

\int{x^n} \, dx = \frac{x^{n+1} }{n+1} +c

Given  x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

 \int\limits^6_^-6} (x^{5}  + 8 x^{4}  + 2 x^{2}  + 5 x + 15) )dx

<em>On integration , we get</em>

=   (\frac{x^{6} }{6} + \frac{8 x^{5} }{5} + 2 \frac{x^{3} }{3} +\frac{5 x^{2} }{2} + 15 x)^{6} _{-6}

F(x) = \int\limits^a_b {f(x)} \, dx = F(b) -F(a)

= (\frac{6^{6} }{6} + \frac{8 6^{5} }{5} + 2 \frac{6^{3} }{3} +\frac{5 6^{2} }{2} + 15X 6) - ((\frac{(-6)^{6} }{6} + \frac{8 (-6)^{5} }{5} + 2 \frac{(-6)^{3} }{3} +\frac{5 (-6)^{2} }{2} + 15 (-6))

After simplification and cancellation we get

 =  \frac{2 X 8 X (6)^{5} }{5} + \frac{2 X 2 X (6)^3}{3} + 2 X 15 X 6

on calculation , we get

= \frac{124,416}{5} + \frac{864}{3} + 180

On L.C.M  15

= \frac{124,416 X 3 + 864 X 5 + 180 X 15}{15}

= 25 351.2 units²

<u><em>Conclusion</em></u>:-

<em>The area of the region between the graph of the given function and the x-axis = 25,351 units²</em>

6 0
2 years ago
Suppose it is found that a certain model of car sells y= -1.6(x-2)^2 + 4.8(x-2) + 16 cars per week, where x is the number of sho
Vilka [71]

Answer:

Approximately 4 shops would be the best number of shops which the car is sold, and the number of cars is 20.

Step-by-step explanation:

This is a quadratic function. Therefore, the first thing you need to do is assume some values for x, and then, calculate the value of y, (which would be the number of cars sold). In this way, you can do the graph.

Watch the following attachment, which is a document of excel, showing the graph and some values of x, that I assume

Now, even if you don't have the graph you can estimate the number of shops with the following expression of the summit:

X = -b / 2a

Where:

a: number that goes along with the x elevated.

b: number that goes along with the x, but without being elevated.

In this equation, the first thing we need to do, is rearrange it, that's because we have a (x-2) in the equation, and this could be really annoying.

First let's solve the (x-2)^2

(x-2)^2 = (x-2)(x-2) = x^2 - 2*2x + 2^2 = x^2 - 4x + 4

This is now multiplied by -1.6:

-1.6x^2 + 6.4x - 6.4

Now, multiply 4.8 by x-2:

4.8x - 9.6

Finally, let's arrange this:

-1.6x^2 + 6.4x - 6.4 + 4.8x - 9.6 + 16

-1.6x^2 + 11.2x - 6.4 - 9.6 + 16 = -1.6x^2 + 11.2x

This means that the graph do not have a "y" intercept, and the values of a and b are -1.6 and 11.2, therefore, we can estimate the best number of shops, calculating the summit of the graph (This is because s a quadratic function, and the graph is a parable, and the minimum or maximum point of the graph is reached in the summit)

Summit has X and Y values, the x value is (see formula above):

X = -11.2 / 2 * -1.6 = 3.5

and for the y value, just replace the X value in the equation:

Y = -1.6(3.5)^2 + 11.2(3.5) = -19.6 + 39.2 = 19.6

With this we can conclude that the best number of shops that sells this model of car, is 4 (rounded) and they all sell 20 cars (also rounded). See the graph below in the attachment.

Download xlsx
4 0
3 years ago
Read 2 more answers
Which of the following functions would result in a graph that is shifted three units to the left of g(x) = 4logx
Ber [7]
Replace the x by x+3

so it would be
4log(x+3)
4 0
3 years ago
Read 2 more answers
A plot of land has an area of 1,089,000 square feet.The conversion factors between different area measures are shown below.27,87
IgorC [24]

Part A) 24.79 acres

1) Since that plot has an area of

1,089,000ft^2=1.08\times10^6ft^2

And the number of units must be between 10 and 10² units.

Part A)

\begin{gathered} 27,878,400ft^2=2.78784\times10^7ft^2=1m^2 \\ 43560ft^2\text{ =4.356 }\times10^4ft^2\text{ = 1 acre} \end{gathered}

2) Let's convert them to the apparently plausible units, see if it fits within the given interval.

\begin{gathered} \frac{1.08\times10^6}{4.356\times10^4}=24.79\text{ acres} \\ \frac{1.08\times10^6}{2.78784\times10^7}=0.03m^{2} \end{gathered}

We can see that 0.03 m² does not belong to the given interval.

3) Hence, the answer is 24.79 acres.

7 0
1 year ago
What is the missing term in the factorization?
jasenka [17]
  • <em>Answer:</em>

<em>the missing term is 5</em>

  • <em>Step-by-step explanation:</em>

<em>Hi there ! </em>

<em>12x² - 75 = </em>

<em>= 3(4x² - 25)</em>

<em><u>use formula</u></em><em> a² - b² = (a - b)(a + b)</em>

<em>= 3(2x - 5)(2x + 5)</em>

<em>= 3(2x + 5)(2x - 5) </em>

<em>the missing term is 5</em>

<em>Good luck !</em>

4 0
3 years ago
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