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baherus [9]
3 years ago
11

The answer to all of these problems

Mathematics
1 answer:
-BARSIC- [3]3 years ago
4 0
1) area of a cicular pool
area of a circle=πr^2   d=2.5 then r=2.5/2
A=3.14 *(2.5/2)^2
A=4.906m^2 A=4.9m^2

2) arae of a coin 
<span>(if i read it right d=15mm?)
</span>A=πr^2   d=15 then r=15/2
A=3.14*(15/2)^2 =176.6mm^2


Rest all are same problems u try to solve it
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If x Is a real number such that x3 = 64, the x2 + x equals what?
Annette [7]

Answer:

20

Step-by-step explanation:

Assuming that the equation is x³ = 64, that can be solved by putting cube root on both sides like so: ∛(x³) = ∛64, which simplifies to <em>x = 4</em>.

Plugging that into our expression gives us <em>4² + 4</em>, which is 20.

7 0
3 years ago
Plz I need help with the last 2 and plz simplify then
GalinKa [24]

Answer:

c) (8^6) / 8 = 32768

d) (7^8) / (7^6) = 49

Step-by-step explanation:

8 0
2 years ago
Plz answer the following file attached
Finger [1]

Answer:

i like how to tell us to answer something with no file

Step-by-step explanation:

6 0
2 years ago
Which shows a correct order to solve this story problem? Maxine had to pay $1.46 in sales tax on her purchases. She bought 3 bar
romanna [79]
Choice B would be the correct answer. I hope that helps! :D
4 0
3 years ago
Consider the case of a triangle with sides 5, 12, and the angle between them 90°.
Daniel [21]

Answer:

a) Applying Pithagoras Theorem

b) Trigonometric relations

c) No we can not

d) No we can not

e) See step-by-step explanation

f) See step-by-step-explanation

Step-by-step explanation:

a) The easiest method for calculating the missing side is applying Pithagoras Theorem

c²  =  a²  +  b²

c²  =  (5)²  +  (12)²      ⇒  c²  = 25 + 144    ⇒ c²  =  169    ⇒  c  = 13

b) The easiest method to find the missing angles, is to calculate the sin∠ and then look for arcsin fuction in tables.

sin ∠α = 5/13    sin ∠α = 0.3846    ⇒      arcsin (0.3846 )   α  = 23⁰

Now we can either get the other angle subtracting 180 - 90 - 23 = 67⁰

Or calculating sinβ = 12 /13    sinβ = 0.9230  arcsin(0.9230)   β = 67⁰

c) The law of cosines should not be applied to right triangles, in fact for instance in our particular case we have:

Question a)

c²  = a² + b² - 2*a*b*cos90⁰   (law of cosines ) but cos 90⁰ = 0

then c²  = a² + b² which is the expression for theorem of Pithagoras

In case you look for calculating the missing angles

c²  = a²  +  b²  - 2*5*13*cos α

169 = 25  +  144 - 2*5*13* cos α

As you can see 169 - 25 - 144 = 0

Then we can not  apply law of cosine in right triangles, we shoul apply trigonometric relations and Pithagoras theorem, and as we saw you can get the expression of Pithagoras theorem from cosine law

c²  =  a²  +  b²  - 2*a*b*cos∠90°    cos ∠ 90°  = 0

Then     c²  =  a²  +  b²

3 0
2 years ago
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