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Degger [83]
3 years ago
6

Please help!! I'll give brainliest and all 35 of my points!

Mathematics
1 answer:
Volgvan3 years ago
3 0

Answer:

Step-by-step explanation:

You need to mutiply and slove the promble than you will get the answer

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(25 points!!!!!) solve for <2
stiv31 [10]

Step-by-step explanation:

135 = <2 + 86 [exterior angle of triangle is equal to the sum of its oppsite two interior angles]

or, <2 = 135 - 86

so, <2 = 49°

8 0
2 years ago
What is the value of 2 + b(a? + 4) when a = 2 and b = 4?<br> A 22<br> B 34<br> C 2<br> D 48
lisov135 [29]

Answer: 26

Step-by-step explanation:

lets replace a and b with the numbers provided

2+4(2+4)=2+4(6)=2+24=26

4 0
3 years ago
NEED THIS ASAP GUYS PLEASE DONT HAVE ME WRONG
Murrr4er [49]

Answer:

its 12

Step-by-step explanation:

LCM of 3,4 and 6 is 12

3 0
3 years ago
Solve the equation. Check for extraneous answers
Lady bird [3.3K]
The answer is A i hope this helps 
7 0
4 years ago
There are 8 tennis players in a round robin tournament, which means each team will play every other team once. How many matches
Aliun [14]
<h3>Answer:  28</h3>

==========================================================

Explanation:

Method 1

Imagine a table with 8 rows and 8 columns to represent all possible match-ups. You can actually draw out this table or just think of it as a thought experiment.

There are 8*8 = 64 entries in the table. Along the northwest diagonal, we have each team pair up with itself. This is of course silly and impossible. We cross off this entire diagonal so we drop to 64-8 = 56 entries.

Then notice that the lower left corner is a mirror copy of the upper right corner. A match-up like AB is the same as BA. So we must divide by 2 to get 56/2 = 28 different matches.

----------------------------------

Method 2

There are 8 selections for the first slot, and 8-1 = 7 selections for the second slot. We have 8*7 = 56 permutations and 56/2 = 28 combinations.

----------------------------------

Method 3

Use the nCr combination formula with n = 8 and r = 2

n C r = \frac{n!}{r!(n-r)!}\\\\8 C 2 = \frac{8!}{2!*(8-2)!}\\\\8 C 2 = \frac{8!}{2!*6!}\\\\8 C 2 = \frac{8*7*6!}{2!*6!}\\\\ 8 C 2 = \frac{8*7}{2!}\\\\ 8 C 2 = \frac{8*7}{2*1}\\\\ 8 C 2 = \frac{56}{2}\\\\ 8 C 2 = 28\\\\

There are 28 combinations possible. Order doesn't matter (eg: match-up AB is the same as match-up BA).

Notice how the (8*7)/2 expression is part of the steps shown above in the nCr formula.

7 0
2 years ago
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