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never [62]
3 years ago
9

6/120 is close to 0, 1/2 or 1

Mathematics
1 answer:
Tema [17]3 years ago
3 0

Answer:

0

Step-by-step explanation:

duh

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Jade says that the absolute value of a number and the opposite of a number is the same thing. Is Jade correct? Use examples to h
avanturin [10]

Answer:

No, the absolute value of a number is different from the opposite.

Step-by-step explanation:

For example, the absolute value of 4 is 4.

l4l = 4

But the opposite of 4 is -4.

Absolute value is ALWAYS positive, but the opposite of a positive number is a negative number.

8 0
3 years ago
Rudolf has a pool that has a diameter of about 24.26 mm. What is the area of the pool in terms of pi
bonufazy [111]

Answer:

   = 147.1369 pi

Step-by-step explanation:

The diameter is 24.26

The radius is d/2 = 24.26/2 =12.13

The area of a circle is

A = pi r^2

   = pi (12.13)^2

   = 147.1369 pi

6 0
3 years ago
Read 2 more answers
If i have a forest composed of 25 species of trees, each with a known abundances, how many events are there in the sample space
Vsevolod [243]
There are 25 species of trees, each with a known abundances. The question is how many possible ways to randomly select one tree there are.
We should calculate the number of combinations. Combinations, because we select item/s from a collection. In this case, when we select only one item, the combination is also a permutation. From set of n objects we select r. In our case: n=25, r=1. 
The equation is: n!/r!(n-r)!= 25!/1!*24!=25*24!/24!=25
There are 25 different outcomes (events).
3 0
3 years ago
HELP!! GEOMETRY!! WHAT IS THE MEASURE OF ANGLE ABC ?
deff fn [24]
Angle ABC is 70 degrees
7 0
3 years ago
Read 2 more answers
I need help combining functions!
postnew [5]
\bf \begin{cases}
f(x)=\cfrac{2}{x}\\\\
g(x)=\cfrac{x}{x+2}
\end{cases}\qquad g[\quad f(x)\quad ]=\cfrac{[f(x)]}{[f(x)]+2}

\bf (g\circ f)(x)\iff g[\quad f(x)\quad ]=\cfrac{\boxed{\frac{2}{x}}}{\boxed{\frac{2}{x}}+2}
\\\\\\
g[\quad f(x)\quad ]=\cfrac{\frac{2}{x}}{\frac{2x+2}{x}}\implies g[\quad f(x)\quad ]=\cfrac{2}{x}\cdot \cfrac{x}{2x+2}
\\\\\\
g[\quad f(x)\quad ]=\cfrac{2x}{2x^2+2x}\implies  g[\quad f(x)\quad ]=\cfrac{2x}{2x(x+1)}
\\\\\\
g[\quad f(x)\quad ]=\cfrac{1}{x+1}
5 0
3 years ago
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