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4 years ago

TRUE OR FALSE!!it is possible for a system of linear equations to have no solution

1 answer:

4 0

True
if the lines are paralell, there is no intersection and therefor no solution

example
y=3x+4
and
y=3x+10
or

3x+2y=4 and
3x+2y=9

true

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3 years ago

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Which set of factors matches theses partial products? 3x50=150. 3x7=21

maksim [4K]

Answer:

Step-by-step explanation:

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3 years ago

At a campground, kayak rental company A charges a fixed amount of $10 plus $8 per hour for renting a one-person kayak. Company B

JulijaS [17]

Answer:

2hours

Step-by-step explanation:

Given data

Company A

charges a fixed amount of $10 plus $8 per hour

let the number of hours be x

and the total be y

y= 10+8x----------------1

Company B

charges a fixed amount of $6 plus $10 per hour for a one-person kayak.

let the number of hours be x

and the total be y

y= 6+10x----------------2

Equate 1 and 2 above

10+8x= 6+10x

collcet like terms

10-6= 10x-8x

4= 2x

x= 2hours

Hence after 2 hours the charges will be the same

5 0

3 years ago

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Lemur [1.5K]

Answer:

3x² + 2xy

Step-by-step explanation:

x² + 3xy + 2x² - xy

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6 0

3 years ago

Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.

Ann [662]

Note that if ${x_2}'=x_1$ , then ${x_2}''={x_1}'$ , and so we can collapse the system of ODEs into a linear ODE:

${x_2}''=3{x_2}'-x_2+e^t$
${x_2}''-3{x_2}'+x_2=e^t$

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

$r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0$

so that the characteristic solution is

${x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}$

Now let's suppose the particular solution is ${x_2}_p=ae^t$ . Then

${x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t$

and so

$ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1$

Thus the general solution for $x_2$ is

$x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t$

and you can find the solution $x_1$ by simply differentiating $x_2$ .

7 0

4 years ago