Refer to the figure given below while reading the solution.
Suppose the dog reaches position A when traveled 10 m diagonally towards the opposite side.
And then position B when traveled 5 m towards the right turning 90°.
We can observe that APC is a right triangle with legs of equal length AC. And the coordinates of the point A is (AC, AC).
Also we can observe that APB is a right triangle with legs of equal length AD. Then the coordinates of the point D is (AC, AC-AD).
Hence, the coordinates of B will be (AC+AD, AC-AD).
Now, we since we have the coordinates we can calculate the shortest distances of B from each of the sides.
- The shortest distance of B from PQ = AC-AD
- The shortest distance of B from SR = 44-(AC-AD)
- The shortest distance of B from SP = AC+AD
- The shortest distance of B from RQ = 44-(AC+AD)
So, the average of the shortest distances of B from each side is 
Hence, the average of the shortest distance of B from each side is 22 m
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Answer:
10%
Step-by-step explanation:
The change is 90-100 = -10. As a percentage of the original amount, that is ...
-10/100 × 100% = -10%
The change from 100 to 90 is a reduction of 10%.
A. The answer is yes, because the distribution is approximately a bell curve.
Answer:
The right answer is D ( 12 in )
3 in - - - - > 45 feet
x in - - - - > 180 feet
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45*x=3*180 - - > 45*x=540 - - > x=540/45=12