Answer:
See Below.
Step-by-step explanation:
In the given figure, O is the center of the circle. Two equal chords AB and CD intersect each other at E.
We want to prove that I) AE = CE and II) BE = DE
First, we will construct two triangles by constructing segments AD and CB. This is shown in Figure 1.
Recall that congruent chords have congruent arcs. Since chords AB ≅ CD, their respective arcs are also congruent:

Arc AB is the sum of Arcs AD and DB:

Likewise, Arc CD is the sum of Arcs CB and DB. So:

Since Arc AB ≅ Arc CD:

Solve:

The converse tells us that congruent arcs have congruent chords. Thus:

Note that both ∠ADC and ∠CBA intercept the same arc Arc AC. Therefore:

Additionally:

Since they are vertical angles.
Thus:

By AAS.
Then by CPCTC:

Answer:
<h2>MP ≈ 2.98 cm</h2>
Step-by-step explanation:
Use sine:

We have:

Substitute:

<em>cross multiply</em>
<em>divide both sides by 1,000</em>

Answer:
Use the distributive property to write an equivalent expression 2f + 10 answers: a. f(2 +10) b. 2(f + 5) c. 2(f + 10)
Step-by-step explanation:
Step-by-step explanation:
I can't see good the picture