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Nesterboy [21]
3 years ago
9

-5+ 3= 2) -7 -4 3) 122 × (-9) 4) -6 divided by 3/4

Mathematics
1 answer:
lutik1710 [3]3 years ago
4 0

Answer:

Step-by-step explanation:

1) -5 +3 = -2

When two numbers are in different sign, subtract and the result will have the bigger numbers sign.  The bigger number is 5. so the result is (-2)

2) -7 - 2 = -9

When two numbers have same sign, add and the result will have the common sign

3) 122 * (-9) = - 1098

4) -6 ÷ (3/4)

=(-6)*\frac{4}{3}\\\\=-2*4

= -8

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A pattern exists in the sum of the interior angles of polygons. The sum of the interior angles of a
slega [8]

Answer:

1,620 degrees.

Step-by-step explanation:

It has a steady pattern. 180 x 2 = 360, which is quadrilateral. 180 x 3 = 540, which is a pentagon. so, 180 x 9 = 1,620

8 0
3 years ago
Suppose the initial height of a Pumpkin is 12 feet and the pumpkin is being launched with a velocity of 61 feet per second. Use
iogann1982 [59]
<h2>Hello!</h2>

The answer is:

The maximum height before landing will be 69.7804 feet.

<h2>Why?</h2>

Since there is no information about the angle of the launch, we can safely assume that it's launched vertically.

So, we can calculate the maximum height of the pumpkin using the following formulas:

y=y_o+v_{o}*t-\frac{1}{2}gt^{2}

v=vo-gt

Where,

y, is the final height

y_o, is the initial height

g, is the acceleration of gravity , and it's equal to:

g=32.2\frac{ft}{s^{2} }

t, is the time.

Now, we are given the following information:

y_{o}=12ft\\\\v=61\frac{ft}{s}

Then, to calculate the maximum height, we must remember that at the maximum height, the speed tends to 0, so, calculating we have:

Time calculation,

We need to use the following equation,

v=vo-gt

So, substituting we have:

v=61\frac{ft}{s}-32.2\frac{ft}{s^{2}}*t\\\\-61\frac{ft}{s}=-32.2\frac{ft}{s^{2}}*t\\\\t=\frac{-61{ft}{s}}{-32.2\frac{ft}{s^{2}}}=1.8944s

We know that it will take 1.8944 seconds to the pumpkin to reach its maximum height.

Maximum height calculation,

Now, calculating the maximum height, we need to use the following equation:

y=y_o+v_{o}*t-\frac{1}{2}gt^{2}

Substituting and calculating, we have:

y=y_o+v_{o}*t-\frac{1}{2}gt^{2}

y=12ft+61\frac{ft}{s}*1.8944s-\frac{1}{2}32.2\frac{ft}{s^{2}}*(1.8944s)^{2}

y=12ft+61\frac{ft}{s}*1.8944s-\frac{1}{2}32.2\frac{ft}{s^{2}}*(1.8944s)^{2}\\\\y_{max}=12ft+115.5584ft-16.1\frac{ft}{s^{2}}*(3.5887s^{2})\\\\y_{max}=127.5584ft-57.7780ft=69.7804ft

Hence, we have that the maximum height before the landing will be 69.7804 feet.

Have a nice day!

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iVinArrow [24]

Answer:

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