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Genrish500 [490]
3 years ago
5

Find four fractions between 1/10 and 1/8

Mathematics
1 answer:
Alex17521 [72]3 years ago
6 0

9514 1404 393

Answer:

  5/48, 5/46, 5/44, 5/42

Step-by-step explanation:

We can choose unit fractions with denominators between 8 and 10, separated by (10-8)/5 = 0.4 units:

  1/8.4 = 5/42

  1/8.8 = 5/44

  1/9.2 = 5/46

  1/9.6 = 5/48

__

<em>Check</em>

  • 1/8 = 0.125
  • 5/42 ≈ 0.119
  • 5/44 ≈ 0.114
  • 5/46 ≈ 0.109
  • 5/48 ≈ 0.104
  • 1/10 = 0.100

_____

<em>Additional comment</em>

There are an infinite number of such fractions. We are given unit fractions with different denominators, so it works reasonably well to choose denominators between those given. Then the trick is to convert the fraction to a ratio of integers. In this case, multiplying by (5/5) does the trick.

__

Another approach is to write the fractions with a common denominator, then choose numerators between the ones given. For example, 1/10 = 4/40, and 1/8 = 5/40, so you could write some fractions with numerators between 4 and 5. Possibilities are 4.1/40 = 41/400, 4.3/40 = 43/400, 4.7/40 = 47/400, 4.9/40 = 49/400.

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Let's check each case to determine the solution to the problem.

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The cost of each flower  arrangements is \$28

Statements

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we know that

If the price is marked down by 10 percent

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10\%= \frac{10}{100} =0.10  

(1-0.10)*\$28=0.90*\$28 \\= \$25.20

\$25.20=\$25.20

therefore

The statement case A) is True

<u>case B)</u> If the price is marked down by 25 percent, the new price will be \$21

we know that

If the price is marked down by 25 percent

then

the new price will be

25\%= \frac{25}{100} =0.25  

(1-0.25)*\$28=0.75*\$28 \\= \$21

\$21=\$21

therefore

The statement case B) is True

<u>case C)</u> If the price is marked down by 50 percent, the new price will be \$19

we know that

If the price is marked down by 50 percent

then

the new price will be

50\%= \frac{50}{100} =0.50  

(1-0.50)*\$28=0.50*\$28 \\= \$14

\$14 \neq \$19

therefore

The statement case C) is False

<u>case D)</u> If the price is marked down by 35 percent, the new price will be \$18.20

we know that

If the price is marked down by 35 percent

then

the new price will be

35\%= \frac{35}{100} =0.35  

(1-0.35)*\$28=0.65*\$28 \\= \$18.20

\$18.20=\$18.20

therefore

The statement case D) is True

<u>case E)</u> If the price is marked down by 40 percent, the new price will be \$29.80

we know that

If the price is marked down by 40 percent

then

the new price will be

40\%= \frac{40}{100} =0.40  

(1-0.40)*\$28=0.60*\$28 \\= \$16.80

\$16.80 \neq \$29.80

therefore

The statement case E) is False


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(9\sin2x+9\cos2x)^2=81

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9\sin2x+9\cos2x=9\implies\sin2x+\cos2x=1

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9\sin2x+9\cos2x=-9\implies\sin2x+\cos2x=-1

Recall that

\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta

If \alpha=2x and \beta=\dfrac\pi4, we have

\sin\left(2x+\dfrac\pi4\right)=\dfrac{\sin2x+\cos2x}{\sqrt2}

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\sin2x+\cos2x=\sqrt2\sin\left(2x+\dfrac\pi4\right)=\pm1

Then in the first case,

\sqrt2\sin\left(2x+\dfrac\pi4\right)=1\implies\sin\left(2x+\dfrac\pi4\right)=\dfrac1{\sqrt2}

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(where n is any integer)

\implies2x=2n\pi\text{ or }\dfrac\pi2+2n\pi

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and in the second,

\sqrt2\sin\left(2x+\dfrac\pi4\right)=-1\implies\sin\left(2x+\dfrac\pi4\right)=-\dfrac1{\sqrt2}

\implies2x+\dfrac\pi4=-\dfrac\pi4+2n\pi\text{ or }-\dfrac{3\pi}4+2n\pi

\implies2x=-\dfrac\pi2+2n\pi\text{ or }-\pi+2n\pi

\implies x=-\dfrac\pi4+n\pi\text{ or }-\dfrac\pi2+n\pi

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x=0,\dfrac\pi4,\dfrac\pi2,\dfrac{3\pi}4,\pi,\dfrac{5\pi}4,\dfrac{3\pi}2,\dfrac{7\pi}4

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Answer:

A) points at which paths intersect : (1,1,1) ; (2,4,8)

B) DNE

Step-by-step explanation:

A) To find the points in which the particle paths intersect, it is necessary to find the values of t for which the three components of both vectors are equal:

t_1=1+2t_2\\\\t_1^2=1+6t_2\\\\t_1^3=1+14t_2

you replace t1 from the first equation in the second equation:

(1+2t_2)^2=1+6t_2\\\\1+4t_2+4t_2^2=1+6t_2\\\\4t_2^2-2t_2=0\\\\t_2(2t_2-1)=0\\\\t_2=0\\\\t_2=\frac{1}{2}

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t_1=1+2(0)=1\\\\t_1=1+2(\frac{1}{2})=2

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t=1+2t\\\\t=-1

This values does not have a physical meaning, then, the particle do not collide

answer: DNE

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