Answer:
3
Step-by-step explanation:
Usually, when there is contamination the smallest amount can have huge ramifications in the data collected. In this scenario, if in a "clean" environment the trait is found in 2/10 frogs then anything above this number should be considered contaminated. This is because data above this ratio would be considered uncommon or rare and this unique occurrence can be most likely tied to the only new factor which would be the contamination. Therefore the minimum number of frogs with this trait in the sample would be 3.
<h3>
Answer: 899</h3>
Explanation:
Replace n with 100 and simplify
f(n) = 9n-1
f(100) = 9(100)-1
f(100) = 900-1
f(100) = 899
The 100th term is 899
Answer:
3mil
Step-by-step explanation:
60*6*44=15840
Walks 15,840 feet in 1 hour
15840 feet = 3mil
Se escribe una equacion y se resolve.
Vamos a usar x para representar el peso de la piedra.
En en platillo que tiene la piedra, el peso total es: x + 1/9 + 2/3
En el otro platillo: 1/2 + 1/3
La balanza esta equilibrada por eso los pesos en los platillos son iguales.
x + 1/9 + 2/3 = 1/2 + 1/3
x + 2/18 + 12/18 = 9/18 + 6/18
x + 14/18 = 15/18
x = 1/18
Respuesta: La piedra pesa un octavo de kilogramo.
see the attached figure to better understand the problem
we know that
in the right triangle ABC
cos 56°=AC/AB
where
AC is the adjacent side to angle 56 degrees------> the distance from the surveyor to the building
AB is the hypotenuse-----> 148 ft 2 in
56 degrees------> is the angle of elevation
so
cos 56°=AC/AB---------> solve for AC
AC=AB*cos 56°
AB=148 ft 2 in
convert 2 in to ft
1 ft -----> 12 in
x ft------> 2 in
x=2/12-----> x=0.17 ft
AB=148 ft 2 in-----> 148 ft+0.17 ft------> AB=148.17 ft
AC=AB*cos 56°----> AC=148.17*cos 56°------> AC=82.86 ft
convert 0.86 ft to in
0.86 ft=0.86*12-----> 10.32 in
distance AB=82 ft 10 in
the answer is
the distance from the surveyor to the building is 82 ft 10 in