Answer:
λN N(0) = 6
N(t) = N₀e^(λt)
Applying the inital value condition
N(t) = 6e^(λt)
Step-by-step explanation:
Summarizing the information briefly and stating the variables in the problem.
t = time elapsed during the decay
N(t) = the amount of the radioactive substance remaining after time t
λ= The constant of proportionality is called the decay constant or decay rate
Given the initial conditions
N(0) = N₀ = 6
The rate at which a quantity of a radioactive substance decays (
) is proportional to the quantity of the substance (N) and λ is the constant of proportionality is called the decay constant or decay rate :
λN
N(t) = N₀e^(λt) ......equ 1
substituting the value of N₀ = 6 into equation 1
N(t) = 6e^(λt)
1.468*3.14 is around 4.6 so B)
And 65.97/4.6 is about 14.3 so C)
-12x^5y^7
Just sum the power and multiply the constants
The mistake is in step 4. It's correct up to step 3. Step 3 shows: $293.25 * 1/6 (this is correct) Now you must multiply $293.25 by the fraction 1/6, which is the same as dividing $293.25 by 6. Instead, in step 4, $293.25 was multiplied by 6. Step 4 is the mistake.