Salt flows into the tank at a rate of
(1/2 lb/gal) * (6 gal/min) = 3 lb/min
and flows out at a rate of
(Q(t)/60 lb/gal) * (6 gal/min) = 6Q(t) lb/min
The net rate of change of the amount of salt in the tank at time
is then governed by

Solve for
:


![\dfrac{\mathrm d}{\mathrm dt}[e^{6t}Q]=3e^{6t}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dt%7D%5Be%5E%7B6t%7DQ%5D%3D3e%5E%7B6t%7D)


The tank starts with 10 lb of salt, so that Q(0) = 10. This gives us

so that the amount of salt in the tank at time
is given by

Answer:
It's a shared side???? It's a leg of a right triangle??? What are you specifically asking for? I need numbers
Step-by-step explanation:
Answer:
f(t)=-16t^2+8t+2
Step-by-step explanation:
Take the initial velocity(8)put in for vt. Then take height(2) and put in for s. giving you the equation. f(t)= -16t^2+8t+2
No they are have a great day
is there a picture or equation that you can provide ?