One square grid has an area of 400.
Another square grid has an area of 256.
The area of the third grid can be:
(squares in third grid) + 256 = 400
OR
256 + 400 = (squares in third grid)
We get this by applying the Pythagorean theorem.
So, the squares in the third grid can either be 144 or 656. And we only have 144 as an option, so that is your answer.
Your final answer is D. 144.
The formula of density is mass / volume.
So, the volume is equal to the area of the cube by the total height, so the area of the cube is 3x3= 9, and this result multiplied by the height, 9x3 = 27.
Following the formula of density, we have 216 g / 27 cm^3, the result is 8 g/cm^3.
Hope you undestand my procedure XD
For this case we have the following inequality:

The first thing we must do is to graph the linear function:

Then, we must evaluate ordered pairs in the following way:
(x, y)
The ordered pairs that meet the inequality, will be included as part of the graph.
Therefore, the shaded region contains all the ordered pairs that meet the inequality.
Answer: See attached image.
General Idea:
Domain of a function means the values of x which will give a DEFINED output for the function.
Applying the concept:
Given that the x represent the time in seconds, f(x) represent the height of food packet.
Time cannot be a negative value, so

The height of the food packet cannot be a negative value, so

We need to replace
for f(x) in the above inequality to find the domain.
![-15x^2+6000\geq 0 \; \; [Divide \; by\; -15\; on\; both\; sides]\\ \\ \frac{-15x^2}{-15} +\frac{6000}{-15} \leq \frac{0}{-15} \\ \\ x^2-400\leq 0\;[Factoring\;on\;left\;side]\\ \\ (x+200)(x-200)\leq 0](https://tex.z-dn.net/?f=%20-15x%5E2%2B6000%5Cgeq%200%20%5C%3B%20%5C%3B%20%20%5BDivide%20%5C%3B%20by%5C%3B%20-15%5C%3B%20on%5C%3B%20both%5C%3B%20sides%5D%5C%5C%20%5C%5C%20%5Cfrac%7B-15x%5E2%7D%7B-15%7D%20%2B%5Cfrac%7B6000%7D%7B-15%7D%20%5Cleq%20%5Cfrac%7B0%7D%7B-15%7D%20%5C%5C%20%5C%5C%20x%5E2-400%5Cleq%200%5C%3B%5BFactoring%5C%3Bon%5C%3Bleft%5C%3Bside%5D%5C%5C%20%5C%5C%20%28x%2B200%29%28x-200%29%5Cleq%200%20)
The possible solutions of the above inequality are given by the intervals
. We need to pick test point from each possible solution interval and check whether that test point make the inequality
true. Only the test point from the solution interval [-200, 200] make the inequality true.
The values of x which will make the above inequality TRUE is 
But we already know x should be positive, because time cannot be negative.
Conclusion:
Domain of the given function is 
Answer: 24%
Step-by-step explanation: