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2 years ago

Reduce to simplest form. 12/11 - (-2/3) =

Mathematics

2 answers:

andre [41]2 years ago

8 0

Answer:

58/33

Step-by-step explanation:

Agata [3.3K]2 years ago

3 0

Answer:

58 /33

Step-by-step explanation:

Use math-way for math questions:)

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Simplify the following to standard form

irina1246 [14]

Answer:

1, 11x + 3y + 15z

2, 3x + 12y + -5z

Step-by-step explanation:

all you need to do is combined the like terms and make sure the signs (positive and negative signs) are right

4 0

2 years ago

What fraction is equal to the length of the red segment? Please answer in fraction form and how to get the answer

strojnjashka [21]

Answer:
The red segment is from 1/4 to 3/4.
3/4 - 1/4 = 2/4
2/4 = 1/2
1/2

This answer can also be found by seeing there are four equal boxes making up the one larger box, since two out of the four boxes are filled then the fraction would be 2/4, which simplifies to 1/2

6 0

2 years ago

How to solve 43a+10-26a=27

frutty [35]

17a = 17
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5 0

2 years ago

Read 2 more answers

Jolene wants to invest $2000 into a money market account. Interest is to be 6.5% compounded annually, and she wants to take the

timama [110]

Answer:

Interest = 650$

Step-by-step explanation:

Given:

Invest Inv = 2000$, interest rate r = 6.5% compounded annually

and time n = 5 years

Formula for calculation is:

Int = (Inv · r · n) / 100

Int = (2000 · 6.5 · 5) / 100 = 650$

Int = 650$

God with you!!!

3 0

2 years ago

I just need no. a please help me to prove this.

OleMash [197]

Answer: see proof below

Step-by-step explanation:

Given: A + B + C = π and cos A = cos B · cos C

scratchwork:

A + B + C = π

A = π - (B + C)

cos A = cos [π - (B + C)] Apply cos

= - cos (B + C) Simplify

= -(cos B · cos C - sin B · sin C) Sum Identity

= sin B · sin C - cos B · cos C Simplify

cos B · cos C = sin B · sin C - cos B · cos C Substitution

2cos B · cos C = sin B · sin C Addition

$2=\dfrac{\sin B\cdot \sin C}{\cos B \cdot \cos C}$ Division

2 = tan B · tan C

$\text{Use the Sum Identity:}\quad \tan(B+C)=\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}$

Proof LHS → RHS

Given: A + B + C = π

Subtraction: A = π - (B + C)

Apply tan: tan A = tan(π - (B + C))

Simplify: = - tan (B + C)

$\text{Sum Identity:}\qquad \qquad \qquad =-\bigg(\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}\bigg)$

Substitution: = -(tan B + tan C)/(1 - 2)

Simplify: = -(tan B + tan C)/-1

= tan B + tan C

LHS = RHS: tan B + tan C = tan B + tan C $\checkmark$

5 0

2 years ago