I did the math but I got -4 so maybe -14
Answer:
The distance of the helicopter from the bristol is approximately 1<u>2.81 miles</u>
Step-by-step explanation:
Given:
Helicopter flies 10 miles east of bristol.
Then the helicopter flies 8 miles North before landing.
To find the direct distance between the helicopter and bristol.
Solution:
In order to find the distance of the helicopter from the bristol before landing, we will trace the path of the helicopter
The helicopter is first heading 10 miles east of bristol and then going 8 miles due north.
On tracing the path of the helicopter we find that the direct distance of the helicopter from the bristol is the hypotenuse of a right triangle formed by enclosing the path of the helicopter.
Applying Pythagorean theorem to find the hypotenuse of the triangle.



Taking square root both sides.

Thus, the distance of the helicopter from the bristol is approximately 12.81 miles
Answer:No solution
Step-by-step explanation:
Answer:
p = 5 and b = 8
Step-by-step explanation:
First, create a system of equations:
2p + 4b = 42
7p + 9b = 107
Solve by elimination by multiplying the top equation by -7 and the bottom equation by 2:
-14p - 28b = -294
14p + 18b = 214
Add these together, and solve for b:
-10b = -80
b = 8
Plug in 8 as b into one of the equations, and solve for p:
2p + 4b = 42
2p + 4(8) = 42
2p + 32 = 42
2p = 10
p = 5
So, p = 5 and b = 8
Answer: The correct identities are: 1 + tan^2x = sec^2x 1 + cot^2x = csc^2x sin^2x + cos^2x = 1 which correspond to B and D
Step-by-step explanation:
T////T
im ok at math if its wrong im sorry T^T